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Ad libitum [116K]
3 years ago
14

If you flip a coin and roll a 666-sided die, what is the probability that you will flip a tails and roll at least a 222?

Mathematics
1 answer:
Rzqust [24]3 years ago
4 0

Answer:

5/12

Step-by-step explanation:

For a coin

Number of sample space = 2

Probability of flipping a tail = 1/2

P(T) = 1/2

For a die

Number of sample space = 6

Let D be the event of rolling at least 2.

D = {2,3,4,5,6}

P(D) = 5/6

P(T) and P(D) = P(T) * P(D)

= 1/2 * 5/6

= 5/12

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cupoosta [38]

Answer:

you need 4 1/3 cups of flower

5 0
2 years ago
Which is the function represented by the table?
padilas [110]

A. x + 5

According to the table, the function is shifted up 5 units.

8 0
1 year ago
Zia was driving his truck on the superhighway. His speed was recorded by the motorway camera between 6:00 am to 8:30 am. He cove
kodGreya [7K]

Answer:

Average speed = 100 km/h

Step-by-step explanation:

Given:

Total distance covered = 250 km

Total time taken = 8:30 am - 6:00 am = 2:30 hours = 2.5

Find:

Average speed.

Computation:

⇒ Average speed = Total distance covered / Total time taken

⇒ Average speed = 250 / 2.5

⇒ Average speed = 100 km/h

6 0
3 years ago
Suppose that from the past experience a professor knows that the test score of a student taking his final examination is a rando
DENIUS [597]

Answer:

n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable who represents the test score of a student taking his final examination. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =73,\sigma =10.5)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

We want to find the value of n that satisfy this condition:

P(71.5 < \bar X

And we can use the z score formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we have this:

P(\frac{71.5-73}{\frac{10.5}{\sqrt{n}}} < Z

And we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=0.94

And by properties of the normal distribution we can express this like this:

P(-0.14286 \sqrt{n} < Z< 0.14286 \sqrt{n} )=1-2P(Z

If we solve for P(Z we got:

P(Z

Now we can find a quantile on the normal standard distribution that accumulates 0.03 of the area on the left tail and this value is: z=-1.881

And using this we have this equality:

-1.881 = -0.14286 \sqrt{n}

If we solve for \sqrt{n} we got:

\sqrt{n} = \frac{-1.881}{-0.14286}=13.167

And then n=13.167^2 =173.369 and if we round up to the nearest integer we got n =174

6 0
3 years ago
Find the area of the following shape, given its curves are made from parts of circles with diameters indicated on the diagram.
Alexxandr [17]

Answer:

222.51 (when rounded)

Step-by-step explanation:

Pi x r squared is the formula to find the area of a circle

153.94 + 12.57 + 56

= 222.51

You basically find the area of each circle by find their diameters. So half of the length shown on each circle.

7 0
2 years ago
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