As you can see there are two triangles but it can be done calculating just for one. First we must understand how formula for area of triangle works.

Where
represents base (hypotenuse) and
as height of the triangle.
We know that:

Using this data we fill the formula.

Hope this helps.
r3t40
Answer:
80% or like 8 squares out of 10 oe=r 4 out of 5 ect
Step-by-step explanation:
Answer:
a) 0.283 or 28.3%
b) 0.130 or 13%
c) 0.4 or 40%
d) 30.6 mm
Step-by-step explanation:
z-score of a single left atrial diameter value of healthy children can be calculated as:
z=
where
- X is the left atrial diameter value we are looking for its z-score
- M is the mean left atrial diameter of healthy children (26.7 mm)
- s is the standard deviation (4.7 mm)
Then
a) proportion of healthy children who have left atrial diameters less than 24 mm
=P(z<z*) where z* is the z-score of 24 mm
z*=
≈ −0.574
And P(z<−0.574)=0.283
b) proportion of healthy children who have left atrial diameters greater than 32 mm
= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm
z*=
≈ 1.128
1-P(z<1.128)=0.8703=0.130
c) proportion of healthy children have left atrial diameters between 25 and 30 mm
=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm
z(30)=
≈ 0.702
z(25)=
≈ −0.362
P(z<0.702)=0.7587
P(z<−0.362)=0.3587
Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4
d) to find the value for which only about 20% have a larger left atrial diameter, we assume
P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.
Then P(z<z*)=0.8 and z*=0.84. That is
0.84=
solving this equation for X we get X=30.648
He weighs 196 lbs and 6 ounces. if you add the pounds (180 to 3, 5, 6)you get 194. then you add he ounces, and remember that there are 16 ounces in a pound and 8 ounces in a cup, (6 to 9, 12, 11) you get 2lbs and 6 ounces. then you add the 2 extra pounds to the 194 and you get, all together, 196 lbs and 6 ounces.