Option A:
V = 1/3 * b^2 * h
V = 1/3 * 10.5^2 * 6
V = 1/3 * 110.25 * 6
V = 220.5
Option B:
V = 1/3 * b^2 * h
V = 1/3 * 3.6^2 * 8
V = 1/3 * 12.96 * 8
V = 34.56
Option C:
V = 1/3 * b^2 * h
V = 1/3 * 4.2^2 * 12
V = 1/3 * 17.64 * 12
V = 70.56
Option D:
V = 1/3 * b^2 * h
V = 1/3 * 6^2 * 8.4
V = 1/3 * 36 * 8.4
V = 100.8
I guess it's 'None of the Above'
D is distance-*2 meters* in 3 hours
Answer:
The width of the rectangle is 75 meters and length is 480 meters.
Step-by-step explanation:
The perimeter of the rectangle = 1110 meters
Let the width of the rectangle = k meters
So,the length of the rectangle = 6k + 30
Now, PERIMETER OF A RECTANGLE = 2(LENGTH + WIDTH)
⇒ 1110 = 2( k + (6k + 30))
or, 1110 = 14 k + 60
or, 14 k = 1110 - 60 = 1050
⇒ k = 1050/14 = 75
Hence, the width of the rectangle is k = 75 meters
and the Length of the rectangle is 6k + 30 = 6(75) +30
= 480 meters
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P=2*(L+l)=46
L+l=46:2
L+l=23
(L+l)^2=529
(L^2+l^2)+2l*L=529
D= V L^2+l^2= 17
L^2+l^2=289
so 289+2l*L=529
2l*L=529-289=240
l*L=240:2
A=120
