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3 years ago

(-4y3 – 5y +16) + (4y2 – y + 9) =

Mathematics

1 answer:

velikii [3]3 years ago

6 0

Answer:

-4y^3 + 4y^2 - 6y + 25

Step-by-step explanation:

<u>Step 1: Distribute the plus</u>

(-4y^3 – 5y +16) + (4y^2 – y + 9)

-4y^3 - 5y + 16 + 4y^2 - y + 9

<u>Step 2: Combine like terms</u>

-4y^3 - 5y + 16 + 4y^2 - y + 9

-4y^3 + 4y^2 - 6y + 25

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A national hockey league rink is 115 feet longer than it is wide. If the perimeter of the rink is 570 feet, find the dimensions

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The length of hockey rink is 200 feet and width of hockey rink is 85 feet.

Step-by-step explanation:

Given,

Perimeter of hockey rink = 570 feet

Width of hockey rink = w

Length of hockey rink = w+115

As a hockey rink is in rectangular shape;

Perimeter of rink = 2(Length + Width)

$570=2(w+115+w)\\570=2(2w+115)\\570=4w+230\\570-230=4w\\340=4w\\4w=340$

Dividing both sides by 4

$\frac{4w}{4}=\frac{340}{4}\\w=85$

Width of hockey rink = 85 feet

Length of hockey rink = 85+115 = 200 feet

The length of hockey rink is 200 feet and width of hockey rink is 85 feet.

Keywords: rectangle, division

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#LearnwithBrainly

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