We can see that the graph touches
without crossing the x-axis (i.e. it is a double solution), and then there's another zero at
(this time it's a crossing zero, so a single solution).
This leads, up to multiple, to the polynomial

If we impose the passing through
we have

So, the polynomial is

Finally, to solve
, simply look at the graph, searching for the points, where the graph is below the x-axis. You can see that this happens only if
, so that's the solution to your question.
Answer:
z^3
Step-by-step explanation:
Z cubed is Z X Z X Z = Z^3
1280*.8=1024
1024*1.09=1116.16
Tax is the last thing added, savings before tax since
missing side is
mi .
<u>Step-by-step explanation:</u>
Here we have the following info from the figure: A right angled triangle with following dimensions



By Pythagoras Theorem :

⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore, missing side is
mi .