The sum of a number and 20 is no more than the sum of the square of the number and 9. Which of the following inequalities can be

Question

4 years ago

5

used to determine this unknown number?

2 answers:

AnnyKZ [126] · Answer 1 · 2021-11-10T04:47:41+03:00

7 0

X+20>x3^+9 i think, idk tho

Artemon [7] · Answer 2 · 2021-11-10T06:42:34+03:00

4 0

Answer:

$x + 20 \leq \sqrt{x} + 9$

Explanation:

The number is x.

The sum of a number and 20 is no more than the sum of the square of the number and 9.

This means that the sum of x and 20 is lesser or equal than the sum of the square of x and 9. So:

$x + 20 \leq \sqrt{x} + 9$