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3 years ago

I need a linear equation.

Mathematics

1 answer:

dimaraw [331]3 years ago

7 0

Answer:

Step-by-step explanation:

Let x be the number of songs:

0.99x = 10 + 0.79x

0.2x = 10

x = 50

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4, 8, 12, 16, 20 24, 36, 40 44 48 52 56 60 64 68 72 76 80 84 88 92 96 100... Those are the multiples of 4. Now find out which ar

Lilit [14]

Answer:

Ok the answer of 6 are 12, 18, 24, 30, 36, 42, and 48. The multiples of 9 are 18,27,36,45,54,63,72,81,90,99,108,117,126,135,144,153,162,171,180,189,198,. Hope it helps!

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3 years ago

Name three numbers whose product is about 9,000

Fed [463]

1x9000
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2x4500
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3 years ago

Read 2 more answers

Please help me with this!!! I will mark brainlist!!!

jeka94

Answer: The value of Angle F = 47

Step-by-step explanation:

6 0

3 years ago

The equation 2x^2 – 8x = 5 is rewritten in the form of 2(x – p)^2 + q = 0. what is the value of q?

QveST [7]

Answer:

q = -13

Step-by-step explanation:

The given equation is:

$2x^{2}-8x=5$

Taking 2 as common from left hand side, we get:

$2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5$

The square of difference is written as:

$(a-b)^{2}=a^2 - 2ab + b^{2}$ Equation 1

If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.

$2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0$

Comparing the above equation with the given equation:

$2(x-p)^{2}+q=0$ , we can say:

p = 2 and q= -13

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3 years ago

SOMEBODY BETTER ANSWER THIS QUESTION OR IMA MAKE YOU EAT MY TOE :)

harina [27]

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3 years ago