Question

Two horses start a race aat the same time. Horse A gallops at a steady rate of 32 feet per second and Horse B gallops at a steady rate of 28 feet per second.After 5 seconds, how much farther will Horse A have traveled?

Answer 1

Answer:

20 feet

Step-by-step explanation:

The speed of horse A is $S_{A}=32\frac{feet}{s}$

The speed of horse B is $S_{B}=28\frac{feet}{s}$

We define the speed as distance divided by time.

Given that the horses started the race at the same time (and assuming in the same position) we can write :

$Speed=\frac{Distance}{Time} \\Distance=(Speed).(Time)$

After 5 seconds for Horse A :

$Distance=(Speed).(Time)=(32\frac{feet}{s}).(5s)=160feet$

After 5 seconds, Horse A will have traveled 160 feet

After 5 seconds for Horse B :

$Distance=(Speed).(Time)=(28\frac{feet}{s}).(5s)=140feet$

After 5 seconds, Horse B will have traveled 140 feet

The difference between the distances : $160feet-140feet=20feet$

is how much farther Horse A will have traveled.

After 5 seconds, The Horse A will have traveled 20 feet farther than the Horse B.

Answer 2

Answer: 20 feet further