What could you use to show that opposite sides are congruent? Which quadrilaterals does it work for?
1 answer:
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<h3>Answer:</h3>
A. y = -1/3x + 2 . . . . . . . . assuming a typo in your problem statement
<h3>Explanation:</h3>The point (0, 2) is the y-intercept. This tells you the equation will be something of the form ...
... y = mx + 2 . . . . . . matching only answer choices A and C
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Knowing this, you can either substitute the values x=3, y=1 into these two equations to see which one works (it is not C), or you can look at the two points and determine the value of the slope.
The slope is ...
... (difference in y)/(difference in x) = (1-2)/(3-0) = -1/3 . . . . . matches choice A
The equation of the line is ...
... y = -1/3x + 2 . . . . . matches answer choice A