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Morgarella [4.7K]

3 years ago

11

Ben put $60 into his savings account each month for years. He spent 60% of his savings on a used car. How much money did Ben hav

e left in his savings account after purchasing the car?
A.
$1,512.00
B.
$2,520.00
C.
$4,032.00
D.
$1,008.00

1 answer:

Vinil7 [7]3 years ago

3 0

A because I don’t know why

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Really need help with this math problem. Thanks!

ohaa [14]

Lana = x
Pam = 0.5x - 0.05
Cheryl = 0.5x - 0.05 + 3.10

Total 89$ = Lana + Pam + Cheryl

89 = x + 0.5x - 0.05 + 0.5x - 0.05 + 3.10
89 = 2x + 3
89 - 3 = 2x
86 = 2x
86/2 = x
43 = x

then Pam = 0.5(43) - 0.05
= 21.50 - 0.05
= 21.45

Cheryl = 21.45 + 3.10
= 24.55

3 0

4 years ago

Is this relation a function

a_sh-v [17]

Answer:

yes

Step-by-step explanation:

every value of the domain only has one corresponding value

3 0

4 years ago

What is the slope of the line of (6,22) and (15,55) please simplify

Dennis_Churaev [7]

Answer:

11/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(55-22)/(15-6)

m=33/9

simplify

m=11/3

5 0

4 years ago

What must you multiply each of these numbers by to get 1,000? <br> 250, 125, 25, 500, 200, 50

max2010maxim [7]

Step-by-step explanation:

1. 250×4=1000

2.125×8=1000

3. 25×40=1000

4. 500×2=1000

5. 200×5=1000

6. 50×20=1000

3 0

2 years ago

Suppose that P(A|B)=0.2, P(A|B')=0.3, and P(B)=0.7. What is the P(A)? Round your answer to two decimal places (e.g. 98.76).

nata0808 [166]

Answer: $P(A) = 0.23$

Step-by-step explanation:

Given :

$P(A/B) = 0.2$

$P(A/B^{1})=0.3$

$P(B)= 0.7$

$P(A) = ?$

From rules of probability :

$P(A) = P(AnB) + P(A n B^{1})$ ........................... equation *

$P(A n B)$ can be written as $P(A/B)$ x $P(B)$

Also , $P(A/B^{1})$ can be written as $P(A/B^{1})$ x $P(B^{1})$

substituting into equation * , we have

$P(A) = P(A/B)$ $P(B) + P(A/B^{1})P(B^{1})$

since P(B) = 0.7, then $P(B^{1}) = 1 - P(B) = 0.3$

so , substituting each values , we have

$P(A) = (0.2)(0.7) + (0.3)(0.3)$

$P(A) = 0.14 + 0.09$

$P(A) = 0.23$

4 0

4 years ago