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3241004551 [841]
3 years ago
8

Solve each problem by forming a pair of simultaneous equations:

Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
7 0

Answer:

5.5, 9.5

Step-by-step explanation:

Let x and y be the numbers

x+y = 15

x-y = 4

Add the two equations together to eliminate y

x+y = 15

x-y = 4

------------------

2x = 19

Divide by 2

2x/2 =19/2

x = 9.5

Now find y

x+y = 15

9.5+y = 15

Subtract 9.5

x = 15-9.5

x =5.5

Komok [63]3 years ago
4 0

Answer:

11/2 and 19/2

Step-by-step explanation:

We have to make a system of equations:

1) X + Y = 15

2) X - Y = 4

Working on the first one:

X = 15 - Y

And now let's plug it in the second one:

(15 - Y) - Y = 4

15 - 2Y = 4

2Y = 11

Y = 11/2

Let's substitute this in one of the two equations:

X + 11/2 = 15

X = 19/2

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Answer:


Step-by-step explanation:

Given that prices for a pair of shoes lie in the interval

[80,180] dollars.

Delivery fee 20% of price.  

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(1/20th of price)

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Hence f(c) = c+c/20 = 21c/20

The domain of this function would be c lying between 80 to 180

So domain =[80,180]

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Amount to be repaid = 42 dollars

Once he received this amount, the price would be

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=[84, 189]

Since now Albert has 147 dollars, he can afford is

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6 0
3 years ago
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maxonik [38]
Hope this helps you!

5 0
3 years ago
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Solve y^2+7y+12=0 by completing the square.​
kkurt [141]

Answer:

y = -3, -4

Step-by-step explanation:

Formula is (b/2)^2

So...

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y = -3, -4

8 0
3 years ago
A- p=5<br> B- p=6<br> C- p=7 <br> D- p=8
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

4 (0 -2)

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2 years ago
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