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Dimas [21]
3 years ago
6

What is a segment that connects the midpoints of two sides of a triangle?

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0

midsegment is the segment connecting the midpoints of two sides of a triangle

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PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK
dem82 [27]

Answer:

\huge\boxed{9}

Step-by-step explanation:

\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}

Rule of exponents a^0 = 1 , 1/a^m = a^{-m}

=> \sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}

=> \sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}

Combining same bases

=> \sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}

When bases are same , powers are to be added

=> \sf 2 ^{-16-12+28} * 3^{10-8}

=> \sf 2^{-28+28} * 3^2

=> \sf 2^0 * 3^2

=> \sf 3^2

=> 9

8 0
3 years ago
How do you know if two lines are parallel?
GalinKa [24]
The lines never intersect or touch should be the answer.

Hope this helps/works.
4 0
3 years ago
Read 2 more answers
One week, Kerry travels 125 miles and uses 5 gallons of gasoline. The next week, she travels 175 miles and uses 7 gallons of gas
bazaltina [42]
This is good information, but the question part is missing. Put the question in the comments and I'll try my best to help!
6 0
2 years ago
If an object is shot with an initial velocity of 160 ft/sec, what is the smallest initial angle will you need to obtain a horizo
MrRissso [65]
To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
3 0
3 years ago
The number 85 is decreased to 83. What is the percentage by which the
Readme [11.4K]

Answer:

~ 2.3%

Step-by-step explanation:

A percentage is a amount divided by the total.

2/85 (2 is the amount decreased) 0.02352941176470588235294117647059‬

That makes around 0.023.

That multiplied by 100 is 2.3 and that makes the percentage.

So yeah.

5 0
2 years ago
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