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Dimas [21]
3 years ago
6

What is a segment that connects the midpoints of two sides of a triangle?

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0

midsegment is the segment connecting the midpoints of two sides of a triangle

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HELP PLEASE ITS DUE IN 10 MIN Use algebraic strategies to solve for x.
mr Goodwill [35]

Answer:

x = 4, x ≠ -1

Step-by-step explanation:

√3x + 4 = x

(√3x + 4)² = x² (Square both sides to get rid of the radical.)

3x + 4 = x²

0 = x² - 3x - 4 (Set everything to 0 by moving everything to one side.)

0 = (x - 4)(x + 1) (Factor.)

x = 4   x = -1

Now we need to check for extraneous solutions:

√3(4) + 4 = 4

√12 + 4 = 4

√16 = 4

4 = 4

√3(-1) + 4 = -1

√-3 +4 = -1

√1 = -1

1 ≠ -1

-1 is an extraneous solution.

8 0
2 years ago
-5(6v-w-1) <br> Distributive prot
krok68 [10]

Answer:

-30v + 5w + 5

Step-by-step explanation:

-5(6v - w - 1) =

Multiply -5 by each term inside the parentheses.

= -5 * 6v - (-5) * w - (-5) * (-1)

= -30v + 5w + 5

5 0
3 years ago
Factor completely:<br><br> 7r^2− 64r + 64
poizon [28]

Answer:

7r^2-64r+64

49r-64r+64

-15r+64

Step-by-step explanation:

8 0
2 years ago
What is the exterior angle of triangle ABC<br><br> These are the points:<br> A=3, B=10, C=6
igor_vitrenko [27]
Based off of  what I can see in the  photo (its too blurry to know for sure) and what I think you're asking:

The angle of a triangle always adds up to 360degrees, so base it on that and the acute and obtuse  angles  and get the degrees from there, the angle would be those degrees you find or <10, 5, 4 (what I assume  is a 5)

3 0
3 years ago
Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 12 feet a
Brrunno [24]

Answer:

Step-by-step explanation:

The student needs to check all algebraic and mathmatical calculations for errors and typos.  I'm old and have been prone to making mistakes.

Cylinder A DIAMETER 12 ft and Height 13 ft

Cylinder B DIAMETER 10 ft and Height 16 ft

After pumping How much water remains in cylinder A

Volume of a cylinder  =  π(radius)²h is the normal form since they provided the diameter I will use     Volume of a cylinder  =  π(diameter/2)²h

Water remaining in A = Volume of A  - Volume of B   =  

VolA  - VolB  =  π(D for A/2)²H of A  -   π(D for B/2)²H of B

             writing if a little more condensed

VolA  - VolB  =  π(D for A/2)²H of A  -   π(D for B/2)²H of B

    Va - Vb    =   π(Da/2)²Ha  -   π(Db/2)²Hb

                     =  π [(Da²/2²)Ha - (Db²/2²)Hb]      factored out the π

                     =  π/4 [ Da²Ha  - Db²Hb]              factored out the (1/2)²

             I can't think of any other algebraic steps

Va - Vb = Water Remaining in Container A  =  π/4 [ Da²Ha  - Db²Hb]            

            =  π/4 [ (12²)(13)  - (10²)(16)]

            =  π/4 [ (144)(13)  - (100)(16)]

            =  π/4 [ 1872 - 1600 ]

            =  π/4 [272]

            =  π [ 272/4 ]  

            =  π [ 136 / 2]

            =  π [ 68 ]

            =  π (68)

            =  213.6  ft³             rounded to the nearest tenth

I checking my answer by using  V = πr²h         r = d/2

           Va - Vb = π [ra²ha - rb²hb]

                         = π [6²(13)  - 5²(16)]

                         = π [(36)(13) - (25)(16)]

                         = π [ 468 - 400]

                         = 68 π

                         = 213.6 ft³         I got the same answer

       

            =  π

test

   

8 0
2 years ago
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