It's probably 8 actually. Because you measure the AC and the CB and just subtract.
        
             
        
        
        
Answer:
134/15 or 
8 14/15
Step-by-step explanation:
 
        
             
        
        
        
Answer: 5=log_{2}(32)5=log 
2
 
 (32)
Step-by-step explanation:
1. By definition, you have if y=b^{x}y=b 
x
 , then x=log_{b}(y)x=log 
b
 
 (y)
2. Keeping this on mind, you must follow the proccedure shown below:
- You have that:
2^{5}=322 
5
 =32
Where:
\begin{lgathered}x=5\\y=32\\b=2\end{lgathered} 
x=5
y=32
b=2
 
 
- Substitute values into x=log_{b}(y)x=log 
b
 
 (y) . Then, you obtain:
5=log_{2}(32)5=log 
2
 
 (32<em><u>)</u></em>