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LUCKY_DIMON [66]
3 years ago
12

Solve for y. y^2-xy+3=-xy+y^2

Mathematics
1 answer:
IRISSAK [1]3 years ago
3 0
The answer for your question is 0=-3
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How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
2 years ago
Factor y 2 + 10z - 10y - yz.
dedylja [7]
Y² + 10z - 10y - yz = (y - 10)(y - z)
7 0
3 years ago
I NEED HELP ASAP!!!!!!!!​
exis [7]

Answer:

Bruh what is this

5 0
3 years ago
Read 2 more answers
What is the point-slope form of a line with slope 3 that contains the point (2,1)
ryzh [129]

Answer:

Point slope form:

The equation of line is given by: y-y_1=m(x-x_1)        .....[1]

where m is the slope and a line contains a point (x_1, y_1).

As per the given statement:

Slope(m) = 3

(x_1, y_1). = (2, 1)

Substitute these in [1] we have;

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therefore, the point slope form of a line with slope 3 that contains the point (2, 1) is; y-1=3(x-2)

5 0
3 years ago
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Rectangle A has a width of 3 inches and a length of 5 inches. Part A Rectangle A has the same perimeter as Rectangle B. If its w
Nutka1998 [239]

Answer:

Part A

Rectangle B has a B has a width of 4 inches and a length of 4 inches

Part B

The answers that apply are:

A. Rectangle A has an area of 15 square inches

C. Rectangle B has an area of 16 square inches

D. Rectangle B has a greater area than Rectangle A

Step-by-step explanation:

Let me know if you need any explanation

6 0
3 years ago
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