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3 years ago

Evaluate.(1/5) −1 ⋅ 4^001520

Mathematics

2 answers:

bixtya [17]3 years ago

4 0

(1/5) - 1 • 4^0
(1/5) - 1 • 1
(1/5) -1
(1/5) -1/1
(1/5) - (5/5)
(1-5/5)
-4/5

Gwar [14]3 years ago

3 0

Answer:

-1519 4/5

-1519.8

-7599/5

Step-by-step explanation:

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Determine the quantity needed to replace the question mark to make the scale balance The weight times the distance on both sides

Mariana [72]

Solution :

Given

$W_1$ = weight of the first side

= 6 kg = 6000 g

$D_1$ = distance of the first weight from the triangle.

= 3 m = 300 cm

$D_2$ = distance of the first weight from the triangle.

= 600 cm

Let, $W_2$ = weight of the second side

So, $W_1$ x $D_1$ = $W_2$ x $D_2$

or $W_2=\frac{W_1 \times D_1}{D_2}$

$W_2=\frac{6000\times 300}{600}$

= 3000 g

Therefore, the quantity that is used to replace the question mark in order to make the scale balance is 3000 g.

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4 years ago

Part A and B Please 10 points

Flura [38]

For part a I would say you can’t use that translation to change it back to the original triangle. I tried the rule out for myself

My coordinate was 3, 6 and applied the -7 -6 rule and got -4,0.

Then I used the rule that they have to translate it back which was -6 -7 and there’s no way it can be translated back to 3, 6

So the answer is no the rule can’t be used to translate it back

Can you mark branliest

5 0

3 years ago

Read 2 more answers

\Look at this series: 2, 1, (1/2), (1/4), ... What number should come next?

vazorg [7]

Answer:

If it goes down half of the past one it would be 1/8.

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Step-by-step explanation:

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3 years ago

Each algorithm is applied to a group of 52 sample problems. The new algorithm completes the sample problems with a mean time of

dem82 [27]

Answer:

Therefore we fail to reject the Null hypothesis $H_0$

Because the is no sufficient evidence to support the claim of the alternative hypothesis $H_a$

Step-by-step explanation:

From the question we are told that

Sample size $n_1 =52$

Mean time 1 $\=x_1=24.04\ hours$

Mean time 2 $\=x_2=24.52\ hours$

Standard deviation $\partial _1=5.769$

Standard deviation $\partial _2=5.556$

Level of significance 0.05

The null hypothesis is $H_o: \mu_1=\mu_2$

Alternative hypothesis $H_a: \mu_1$

Generally the test statistics is mathematically represented as

$Z= \frac{\=x_1-\=x_2}{\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}}$

$Z= \frac{24.04-24.52}{\sqrt{\frac{5.769^2}{52}+\frac{5.5562^2}{52}}}$

$Z= -0.4321583379$

$Z= -0.43$

From Table the Z-critical value at $\alpha =0.05\ is\ -1.6449$

Therefore

Zcal> Zcritical

(-0.43)=(-1.645)

Generally we fail to reject the null hypothesis $H_0$ at $\alpha = 0.05$

Therefore we fail to reject the $H_0$

Because the is no sufficient evidence to support the claim of $H_a$

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3 years ago

If a restaurant bills totals $85, what amount should be left as a 15$ tips A. $97.75 B. $11.90 C.$12.25 D. $12.75

Nata [24]

If the total bill is $85, and you want to leave a 15% tip, then you can calculate it as follows:

85 * 15%

= 85 * 15/100

= 85 * 0.15

= 12.75

The amount that should be left as a tip is D. $12.75.

4 0

4 years ago