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3 years ago

Change this radical to an algebraic expression with fractional exponents. √y^2 The exponent on y is:

2 answers:

8 0

The power rule (or law of indices) related to root is given
$x^{ \frac{1}{2} }= \sqrt[2]{x}$

We have $\sqrt{ y^{2} }$
Rewrite according to the rule we have $y^{ \frac{2}{2} } = y^{1}$

The exponent on y is '1'

gulaghasi [49]3 years ago

7 0

Answer:

Step-by-step explanation:

The formula is: $\sqrt[n]{x^m} =x^\frac{m}{n}$

Notice that if a = b, the exponent is 1; so, any base raised to the same power as the index will equal the base.

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Which equation best fits these data? PLEASE HELP

Dimas [21]

Answer:

Step-by-step explanation:

Use a quadratic equation regression calculator.

Plugging in all the points, the equation should come somewhere close to

$y=-0.32x^{2} -1.26x+15.81$

Which is answer choice C.

3 0

4 years ago

Read 2 more answers

50 PTS The table represents an exponential function.

GenaCL600 [577]

Answer:

B: 3/4

Step-by-step explanation:

Since we know this is an exponential function

y= ab^x

where a is the initial value and b is the growth rate or what we multiply by

For the first point x=1 and y = 3/2

3/2 = a b^1

3/2 = a*b

For the second point x=2 and y = 9/8

9/8 = a b^2

Take the second equation over the first

9/8 = a b^2

-------------------

3/2 = a*b

3/4 = b

The growth rate is 3/4

That would also be know as the rate of change

4 0

3 years ago

Read 2 more answers

Please give the answer to all 3!! thank you for your help.

Verizon [17]

Answer

a) PQ = 50

b) PC = 18

PY = 27

c) ZC = 6

ZQ = 18

Explanation

Centroid is a point inside a triangle where all lines drawn from each vertex to the midpoints of opposite side intersect.

Part a

X is the midpoint of PQ. SoPX = XQ.

If PX = 25,

then PQ = 2PX

PQ = 2×25

PQ = 50

Part b

The centroid is alway two thirds away from the vertex.

Also PC = twice CY

PC = 2×9

PC = 18

So, if CY = 9, then PY = 3 × 9

PY = 27

Part c

(i) The centroid is alway two thirds away from the vertex.

If ZC = 12, then CZ =(1/2)QZ

CZ = (1/2) × 12

CZ = 6

(ii) The centroid is alway two thirds away from the vertex.

So, if CZ = 6, then QZ =3 CZ

QZ = 3×6

QZ = 18

7 0

3 years ago

Triangle QST is isosceles, and Line segment R T bisects AngleT. Triangle Q S T is cut by bisector R T. The lengths of sides S T

Katyanochek1 [597]

Answer:

m∠QRT = 90°

m∠QRT = m∠SRT

Step-by-step explanation:

Triangle QST is isosceles with QT ≅ ST. In isoscels triangle QST, angles STR and RTQ are congruent.

RT is angle T bisector, so angles QTR and STR are congruent.

Consider two triangles QTR and STR. In these triangles:

TR ≅ TR (reflexive property);
∠QTR ≅ ∠STR (given);
QT ≅ ST (given).

By SAS postulate, these two triangles are congruent. Two congruent triangles have congruent corresponding sides, so

QR ≅ SR
∠QRT ≅ ∠SRT

Angles QRT and SRT are supplementary (add up to 180°). Since these two angles are congruent, they have the same measure equal to $\frac{1}{2}\cdot 180^{\circ}=90^{\circ}$