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3 years ago

What is the answer to 2x+3y=-13

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

6 0

Answer:

solve for x

x=(-13/2-3y/2

solve for y

y= -13/2-2x/3

Step-by-step explanation:

hope its the answer you where looking for

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9x - 4/x = 3. How to solve this? What is the value of x?

Ket [755]

9x-4/x=3 ok first lets get the like terms together! So 9x+1x=10x rewrite 10x-4=3 add 4 to both sides 10x=7 then divide 10 7/10=.7 x=.7
Or you can do it this way
9x-4/x=3 combine like terms so times -4 to both sides 3*-4=-12 rewrite 9x+x=-12 combine like term (still got some) 9x+1x=10x rewrite 10x=-12 divide 10 to both sides -12/10=-1.2 rewrite x=-1.2 (I'm like 95% sure it's this one) hope this helps!!! Have a nice nite (Don't be afraid to ask me about details on this or another question)!!!

7 0

3 years ago

Please please please

sergiy2304 [10]

Sorry can see good in the pic maybe next time
Sorry

8 0

3 years ago

Pls help!!! What is the annual interest for a principle of $5,500 at a simple interest rate of 4.5%?

Verdich [7]

Answer:

Hi Ok So I might be wrong but Here is my answer

$1237.50

r = 4.5% = 0.045

I = prt

I = 5500*0.045*5

= $1237.50

Hope i helped pls mark me as brain list if I'm correct

Step-by-step explanation:

3 0

3 years ago

PLEASE SHOW WORK

CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

$V = \dfrac{\pi}{3}r^2h$

Taking the derivative of V with respect to time, we get

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)$

$\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)$

Since r is always equal to h, we can set

$\dfrac{dr}{dt} = \dfrac{dh}{dt}$

so that our expression for dV/dt becomes

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)$

$\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}$

Solving for dh/dt, we get

$\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}$

$\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})$

$\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}$

7 0

3 years ago

How do you simplify 875/1000

OverLord2011 [107]

$Find\ GCF(875;\ 1000)$

$875|5\\175|5\\.\ 35|5\\.\ \ 7|7\\.\ \ 1|\\875=\fbox5\times\fbox5\times\fbox5\times7\\\\1000|5\\.\ 200|5\\.\ \ 40|5\\.\ \ \ 8|2\\.\ \ \ 4|2\\.\ \ \ 2|2\\.\ \ \ 1|\\1000=\fbox5\times\fbox5\times\fbox5\times2\times2\times2$

$GCF(875;\ 1000)=\fbox5\times\fbox5\times\fbox5=125\\\\\frac{875}{1000}=\frac{875:125}{1000:125}=\frac{7}{2\times2\times2}=\boxed{\frac{7}{8}}$

8 0

3 years ago