Nivel subatómico: lo integran las partículas más pequeñas de la materia, como son los protones, los neutrones y los electrones.
Nivel atómico: lo componen los átomos, que son la parte más pequeña de un elemento químico que puede intervenir en una reacción.
Nivel molecular: está formado por las moléculas, que se definen como unidades materiales formadas por la unión, mediante enlaces químicos, de dos o más átomos, como por ejemplo una molécula de oxígeno (O2) o de carbonato cálcico (CaCO3).
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The amount of the 30 gram-sample that will remain after 270 years is 6.61 grams
<h3>How to determine the number of half-lives </h3>
We'll begin by obtaining the number of half lives that has elapsed. This can be obtained as follow:
- Half-life (t½) = 96 years
- Time (t) = 270 years
- Number of half-lives (n) =?
n = t / t½
n = 270 / 99
n = 2.8125
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 30 grams
- Number of half-lives (n) = 2.8125
- Amount remaining (N) =?
The amount remaing can be obtained as follow:
N = N₀ / 2^n
N = 30 / 2^2.8125
N = 6.61 grams
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True.
Overlapping food chain is a food web. A food web shows the many different paths plants and animals are connected. eg: A hawk might also eat a mouse, a squirrel, a frog or some other animal.
Answer:
2) CAG - TTC - ACG mutates to CAG - TTC - ACC - ACG
Explanation:
Insertions are mutations in which extra base pairs are inserted into a new place in the DNA. The number of base pairs inserted can range from one to thousands!
In option no. 1: We see that there is not addition of a single or more than one base, but the new base sequence is different from the original sequence at three places i.e: TTA - CAC - G
In option no. 2: The insertion of three bases ACC has been made exactly after TTC, the whole sequence and arrangement of bases remain same except this insertion.
In option no. 3: The first base of the sequence T is replaced with A, and all other sequence is same. This type of mutation is called substitution in which one base is replaced by other.
In option no. 4: The last base of the sequence C is deleted, and is not present in new sequence. This type of mutation is called deletion in which a base is removed from the sequence.
Conclusion: Therefore, the best option is 2, in which whole codon is inserted in the DNA base sequence.
