Write an equation to represent the following: Three consecutive integers add up to 11 more than the smallest.
1 answer:
Answer:
Step-by-step explanation:
First we have to assume the smallest integer.
Let,
the smallest integer is x
So, the other two integers are-
x+1 and x+2
Now,
the sum of these 3 integers is greater than smallest integer by 11
So, we get
x+(x+1)+(x+2) =x+11
This is the required equation.
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