3 years ago

Write an equation to represent the following: Three consecutive integers add up to 11 more than the smallest.

Mathematics

1 answer:

mr Goodwill [35]3 years ago

5 0

Answer:

Step-by-step explanation:

First we have to assume the smallest integer.

Let,

the smallest integer is x

So, the other two integers are-

x+1 and x+2

Now,

the sum of these 3 integers is greater than smallest integer by 11

So, we get

x+(x+1)+(x+2) =x+11

This is the required equation.

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Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

$(26)x = 1$

$(50)x = 1$

and:

$(2^6)^x = 1$

$(5^0)^x = 1$

Solving: $(26)x = 1$ and $(50)x = 1$

$(26)x = 1$

Divide both sides by 26

$x = \frac{1}{26}$

$(50)x = 1$

Divide both sides by 50

$x = \frac{1}{50}$

Solving $(2^6)^x = 1$ and $(5^0)^x = 1$

$(2^6)^x = 1$

Express 1 as 2^0

$(2^6)^x = 2^0$

Remove bracket

$2^{6x} = 2^0$

Cancel out 2

$6x = 0$

Divide both sides by 6

$x = \frac{0}{6}$

$x = 0$

$(5^0)^x = 1$

Express 1 as 5^0

$(5^0)^x = 5^0$

Cancel out 5^0

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Good luck!

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