Write an equation to represent the following: Three consecutive integers add up to 11 more than the smallest.
1 answer:
Answer:
Step-by-step explanation:
First we have to assume the smallest integer.
Let,
the smallest integer is x
So, the other two integers are-
x+1 and x+2
Now,
the sum of these 3 integers is greater than smallest integer by 11
So, we get
x+(x+1)+(x+2) =x+11
This is the required equation.
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Answer: x = 4
Step-by-step explanation:
2x - 3 + 4x = 21
6x - 3 = 21
6x - 3 (+3) = 21 (+3)
6x = 24
24/6
x = 4
Answer: y=-5/2x-4
Step-by-step explanation: Use the slope formula and slope-intercept form y=mx+b to find the equation.
Hope this helps you out! ☺
Answer:
Unless there is more to the question than c = 2 because 30 /5 = 6 and if c is 3 than 3 = 6 so simplify if needed.
Answer:
672.12
Step-by-step explanation:
Integers involve with negative, so D isn't the correct answer the correct answer will be A.