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julia-pushkina [17]
2 years ago
9

Jake has a total of 60 chocolates and sweets for sale.After selling 1/3 of the chocolates and 2/3 of the sweets,he had twice as

many sweets left as chocolates.How many sweets did Jake sell?
Pls list out all steps and explain

Mathematics
1 answer:
sergeinik [125]2 years ago
3 0
Drawing models makes it clearer to compare.

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If the measure of angle 1 the measure of angle 2 = 180 and the measure of angle 3 the measure of angle 2 = 180 then the measure
Vitek1552 [10]
If<span> the degree </span>measure<span> of </span>two<span> complementary </span>angles<span> are in the ratio of </span>1<span>:14, ... These are similar to complementary </span>angles<span>, except </span>their<span> sum is </span>180<span> degrees. ... </span>1<span> = </span>angle 3<span>, (because they are vertical </span>angles<span>), </span>then<span> the </span>measure<span> of </span>angle 3<span> = y - 5.</span>
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3 years ago
PLX ANSWER THIS!!! I BEG YOU. ASAP!!! THX!! =UwU=
kodGreya [7K]

It should be noted that the relationship is not linear based on the information illustrated as the difference between the numbers aren't the same.

<h3>How to illustrate the information?</h3>

It should be noted that an equation is simply used to illustrate and express the relationship between the variables.

It should be noted that for the relationship to be linear, it's essential that they've the same relationship between them.

When x = 1, y = 4.5. The

When x = 2, y = 6.5

When x = 3, y = 8.5

When x = 4 y = 11.5

It should be noted that there's a difference of 2 at first but between 3 and 4, there is. a difference of 3.

Therefore, the relationship is not linear.

Learn more about equations on:

brainly.com/question/2972832

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5 0
10 months ago
If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.
nydimaria [60]

Answer:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

Step-by-step explanation:

Given

\cos(\theta) = -\frac{2}{3}

\theta \to Quadrant III

Required

Determine \tan(\theta) \cdot \cot(\theta) + \csc(\theta)

We have:

\cos(\theta) = -\frac{2}{3}

We know that:

\sin^2(\theta) + \cos^2(\theta) = 1

This gives:

\sin^2(\theta) + (-\frac{2}{3})^2 = 1

\sin^2(\theta) + (\frac{4}{9}) = 1

Collect like terms

\sin^2(\theta)  = 1 - \frac{4}{9}

Take LCM and solve

\sin^2(\theta)  = \frac{9 -4}{9}

\sin^2(\theta)  = \frac{5}{9}

Take the square roots of both sides

\sin(\theta)  = \±\frac{\sqrt 5}{3}

Sin is negative in quadrant III. So:

\sin(\theta)  = -\frac{\sqrt 5}{3}

Calculate \csc(\theta)

\csc(\theta) = \frac{1}{\sin(\theta)}

We have: \sin(\theta)  = -\frac{\sqrt 5}{3}

So:

\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}

\csc(\theta) = \frac{-3}{\sqrt 5}

Rationalize

\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}

\csc(\theta) = \frac{-3\sqrt 5}{5}

So, we have:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)

Substitute: \csc(\theta) = \frac{-3\sqrt 5}{5}

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}

Take LCM

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

6 0
3 years ago
What is the slope of the line in the graph
Rzqust [24]

Answer:

In the pic

Step-by-step explanation:

First of all, in order to solve it you need to find the dots where the function crosses x line and y line.

Then, I named each dot according to the formula.

After that, it's just simple math.

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

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2 years ago
Karisha drew pentagon A on a coordinate grid. She then performed a rotation followed by a dilation with scale factor 5 to produc
alex41 [277]

Answer:

A.

Step-by-step explanation:

Rotation is a transformation that turns a figure about a fixed point. An object and its rotation image are the same shape and size, but the figures may be turned in different directions. So, rotation gives us two congruent pentagons.

Dilation is a transformation that produces an image that is the same shape as the original (similar to original), but is a different size. So, dilation gives us two similar pentagons.

A sequence of rotation and dilation produces pentagon that is similar to the initial, but not congruent.

In attached diagram you can see the pictorial representation:

  • pentagon FGHIJ is the rotation image of pentagon ABCDE
  • pentagon KLMNO is dilation image of pentagon FGHIJ

5 0
2 years ago
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