Question

The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by factoring.
What is the constant of the quadratic expression in this equation?

x2 + x + ___ = 0
Help quick please, its timed

Answer 1

Answer:

The constant of the quadratic equation is -420

Step-by-step explanation:

Let

x ----> the first consecutive integer (smaller integer)

x+1 ---> the second consecutive integer

we know that

$x(x+1)=420$

Apply distributive property left side

$x^2+x=420$

subtract 420 both sides

$x^2+x-420=420-420$

$x^2+x-420=0$

therefore

The constant of the quadratic equation is -420