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olga2289 [7]
3 years ago
6

Is ✓ 10 greater than, less than or equal to 5? Use the drop-down menus to explain your answer.

Mathematics
2 answers:
Daniel [21]3 years ago
7 0

Answer:

It is less than 5. I don't know how to help you with the rest.

Step-by-step explanation:

Sophie [7]3 years ago
7 0

Answer:

Step-by-step explanation:

✓9 = 3

And

✓16=4

=> ✓10 is between number 3 and 4

=> ✓10 is less than 5

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What is the value of x?<br><br> Enter your answer in the box.<br><br><br> cm
pochemuha

Answer:

 =94 cm

Step-by-step explanation:

Using the Triangle angle bisector theorem

We can find the value for YK

TV         VY

------- = -----------

TK         YK


95.2         34

------- = -----------

168         YK

Using cross products

95.2 * YK = 34* 168

Divide each side by 95.2

YK = 34* 168/95.2

YK =60

We want to find VK

VK = VY+YK

     = 34+60

     =94 cm

3 0
3 years ago
Find the missing length
natka813 [3]

Answer:

x = 45

Step-by-step explanation:

Corresponding sides of similar triangles will be in same ratio.

\dfrac{x}{x+18}=\dfrac{20}{28}

Cross multiply

x*28 = 20*(x+18)   {Use distributive method}

28x = 20x + 360

28x - 20x = 360

8x = 360

 x = 360/8

x = 45

3 0
2 years ago
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sweet [91]

Answer:

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
How can I construct a truth table for ~(p ^ q)?
bekas [8.4K]
Attached below is a step by step process of arriving at the answer. 

3 0
3 years ago
Solve the system by using a matrix equation.<br> --4x - 5y = -5<br> -6x - 8y = -2
evablogger [386]

Answer:

Solution : (15, - 11)

Step-by-step explanation:

We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )

Row Echelon Form :

\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}

Step # 1 : Swap the first and second matrix rows,

\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}

Step # 2 : Cancel leading coefficient in row 2 through R_2\:\leftarrow \:R_2-\frac{2}{3}\cdot \:R_1,

\begin{pmatrix}-6&-8&-2\\ 0&\frac{1}{3}&-\frac{11}{3}\end{pmatrix}

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}

As you can see our solution is x = 15, y = - 11 or (15, - 11).

4 0
3 years ago
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