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3 years ago

6

100 POINTS NEED ANSWER ASAP

1 answer:

never [62]3 years ago

4 0

Answer:

DOMAIN: {4,5,6,7}

RANGE: {4,4.5,5,5.5,6,6.5,7}

Step-by-step explanation:

here is proof

Mark Brainiest Please

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I really need help on themis math!!!!!!!!!!

cluponka [151]

Midpoint formula is M=( (x1+x²)/2 , (y1+y²)/2 )
let A be there point (x1,y1), our (2,3)

plug into the formula to get

(-2,1)=( (2+x²)/2, (3+y2)/2 )
so -2=(2+x2)/2 and 1=(3+y2)/2

x2=-6 and y2=-1
answer is B

7 0

3 years ago

686.924 to the nearest ten

xenn [34]

<span>686.924 to the nearest ten is 690.0 because the ones place is a number of 5 and above, which means you must move the tens place up 1 value.</span>

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3 years ago

Read 2 more answers

Find the 27th term in the arithmetic sequence of 59,56,53,50

statuscvo [17]

solution:

$A_{n}=59-3(n-1)\\where, n=1,2,3,.....\\A1=59\\A2=56\\A3=53\\A_{n}=a+(n-1)dA27=59+(27-1)3\\=59-78\\=-19\\A27 term is -19$

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3 years ago

Consider two people being randomly selected. (For simplicity, ignore leap years.)

inna [77]

Answer:

$(a) = \frac{144}{133225} \\\\(b) = \frac{1}{365}$

Step-by-step explanation:

Part (a) the probability that two people have a birthday on the 9th of any month.

Neglecting leap year, there are 365 days in a year.

There are 12 possible 9th in months that make a year calendar.

If two people have birthday on 9th; P(1st person) and P(2nd person).

$=\frac{12}{365} X\frac{12}{365} = \frac{144}{133225}$

Part (b) the probability that two people have a birthday on the same day of the same month

P(2 people selected have birthday on the same day of same month) + P(2 people selected not having birthday on same day of same month) = 1

P(2 people selected not having birthday on same day of same month):

$= \frac{365}{365} X \frac{364}{365} =\frac{364}{365}$

P(2 people selected have birthday on the same day of same month) $= 1-\frac{364}{365} \\\\= \frac{1}{365}$

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3 years ago

If two angles are both obtuse, the two angles are equal

yan [13]

If two angles are equal, then the two angles are obtuse.

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3 years ago