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2 years ago

100 POINTS NEED ANSWER ASAP

Mathematics

1 answer:

never [62]2 years ago

4 0

Answer:

DOMAIN: {4,5,6,7}

RANGE: {4,4.5,5,5.5,6,6.5,7}

Step-by-step explanation:

here is proof

Mark Brainiest Please

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A circle with a radius of 10 inches is placed inside a square with a side length of 20 inches. Find the area of the square.

NikAS [45]

I think the answer is A , if y’all don’t get it right I’m sorry

4 0

3 years ago

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Simplify 9x - 4 + 3x

rewona [7]

Answer:

$4(3x - 1)$

Step-by-step explanation:

$9x - 4 + 3x$

Adding 9x & 3x gives 12x.

$= > 12x - 4$

Now taking 4 common from both the terms , we get :-

$4(3x - 1)$

3 0

3 years ago

Ashley has a rectangle made out of paper that is 8 cm by12 cm. She folds it in half twice, first vertically and then horizontall

Svetach [21]

Answer:

$Area =24cm^2$

Step-by-step explanation:

Given

$L = 8cm$

$W = 12cm$

$r = 2$ -- folded twice

Required

The area of the new rectangle

When the length was folder, the new length is:

$l = L/2 = 8cm/2 = 4cm$

When the width was folder, the new width is:

$w = W/2 = 12cm/2 = 6cm$

So, the new area is:

$Area =l * w$

$Area =4cm * 6cm$

$Area =24cm^2$

8 0

2 years ago

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Ymorist [56]

Answer:

The value of x is 7 and y is 14.

Step-by-step explanation:

The steps are :

$- 3x + y = - 7 - - - (1)$

$y = x + 7 - - - (2)$

$(2)→(1)$

$- 3x + (x + 7) = - 7 \\ - 3x + x + 7 = - 7 \\ - 2x = - 14 \\ x = 7$

$substitute \: x = 7 \: \: into \: \: (2)$

$y = 7 + 7 \\ y = 14$

6 0

3 years ago

To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI

nadya68 [22]

Part 1) To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

$\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}$

in this problem we have

$\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})$

therefore

the answer Part 1) is

Law of Sines

Part 2) To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

$g^{2}=h^{2}+i^{2}-2*h*i*cos\ G$

In this problem we have

g=HI

G=angle Beta

substitute

$HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta$

$HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}$

therefore

the answer Part 2) is

Law of Cosines

3 0

2 years ago

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