You throw a die twice. What is the probability of throwing a number less than four and then a six?
1 answer:
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Answer:
Son's age = 24 years
Man's age = 48 years
Step-by-step explanation:
Let's take the age of son as x
Man's age = 2x
Twelve years ago,
Son's age= x-12
Man's age= 2x-12
Man is three times as old as his son so,
Solving for x,
2x-12(1) = x-12(3)
2x-12 = 3x-36
2x-3x = -36+12
-x = - 24
x = 24
So if we substitute the values we get,
Son's age = 24 years
Man's age = 48 years
Hope you understand :)