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Julli [10]
3 years ago
11

A program is run line by line to determine the source of a logic error. Which best describes the specific tool being used?

Computers and Technology
2 answers:
natima [27]3 years ago
4 0

Answer:

A

Explanation:

A compiler is a program that converts instructions into a machine-code or lower-level form so that they can be read and executed by a computer.

They use it step by step. Or AKA. Line by line is what I believe is the correct answer.

riadik2000 [5.3K]3 years ago
3 0

Answer:

c

Explanation:

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Help please!! worth 10 pts! answer quick please!
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Answer:

See Explaination

Explanation:

/*****************************************Hokeemon.java********************************/

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class Hokeemon {

private String name;

private String type;

private int age;

public Hokeemon(String name, String type, int age) {

super();

this.name = name;

this.type = type;

this.age = age;

}

public Hokeemon() {

this.name = "";

this.type = "";

this.age = 0;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public String getType() {

return type;

}

public void setType(String type) {

this.type = type;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

public String liveIn() {

if (this.type.equalsIgnoreCase("dwarf")) {

return "Mountain";

} else if (this.type.equalsIgnoreCase("elf")) {

return "Dale";

} else if (this.type.equalsIgnoreCase("fairy")) {

return "Forest";

} else {

return "Shire";

}

}

public boolean areFriends(Hokeemon other) {

if (this.type.equalsIgnoreCase(other.type)) {

return true;

} else if ((this.type.equalsIgnoreCase("dwarf") && other.type.equalsIgnoreCase("elf"))

|| (this.type.equalsIgnoreCase("elf") && other.type.equalsIgnoreCase("dwarf"))) {

return true;

} else if ((this.type.equalsIgnoreCase("hobbit") && other.type.equalsIgnoreCase("fairy"))

|| (this.type.equalsIgnoreCase("fairy") && other.type.equalsIgnoreCase("hobbit"))) {

return true;

} else {

return false;

}

}

public static Hokeemon[] getData(String file) {

Hokeemon[] hokeemons = new Hokeemon[8];

int i = 0;

try {

Scanner scan = new Scanner(new File(file));

while (scan.hasNextLine() && i < hokeemons.length) {

String line = scan.nextLine();

String[] data = line.split("\\s+");

String name = data[0];

String type = data[1];

int age = Integer.parseInt(data[2]);

hokeemons[i] = new Hokeemon(name, type, age);

i++;

}

scan.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

return hokeemons;

}

public static String getBio(Hokeemon[] hokeemons) {

String s = "";

for (Hokeemon hokeemon : hokeemons) {

s += "I am " + hokeemon.getName() + ": Type " + hokeemon.getType() + ": Age=" + hokeemon.getAge()

+ ", I live in " + hokeemon.liveIn() + "\n";

s += "My friends are: ";

for (Hokeemon hokeemon2 : hokeemons) {

if (hokeemon.areFriends(hokeemon2) && !hokeemon.equals(hokeemon2)) {

s += (hokeemon2.getName() + " ");

}

}

s += "\n";

}

return s;

}

atOverride

public String toString() {

return "Name " + name + ": Type " + type + ": Age=" + age + "\n";

}

}

/*******************************HokeemonMain.java**************************/

import java.util.Arrays;

public class HokeemonMain {

public static void main(String[] args) {

Hokeemon[] hokeemons = Hokeemon.getData("data.txt");

System.out.println(Arrays.toString(hokeemons));

System.out.println(Hokeemon.getBio(hokeemons));

}

}

/**********************************data.txt********************/

Noddy Dwarf 4

Legolas Elf 77

Minerva Fairy 33

Samwise Hobbit 24

Merry Hobbit 29

Warhammer Dwarf 87

Ernedyll Elf 19

Frodo Hobbit 18

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Answer:

Explanation:

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