In an if...else statement, if the code in the parenthesis of the if statement is true, the code inside its brackets is executed. But if the statement inside the parenthesis is false, all the code within the else statement's brackets is executed instead.
Of course, the example above isn't very useful in this case because true always evaluates to true. Here's another that's a bit more practical:
#include <stdio.h>
int main(void) {
int n = 2;
if(n == 3) { // comparing n with 3 printf("Statement is True!\n");
}
else { // if the first condition is not true, come to this block of code
printf("Statement is False!\n"); } return 0;
}
Output:
Statement is False!
Answer:
a.) Incoming packets can be placed in the buffer and played back without the jitter.
b.) Buffering would increase the latency because there would be a delay in time when the packets enter the buffer and the time is released.
Explanation:
Jitter is referred technically as a packet delay variations.
It is variation in the periodicity of periodic events or a signal from target or the true frequency.
Answer: databases, electronic archives, online libraries, spreadsheets (B,C,E,F)
Explanation: I just took the test :)) hope u have a great day and remeber u are beautiful <3
Answer:
The code will get stuck in an infinite loop.
Explanation:
Since val is decreasing by 1 each time it meets the criteria of being smaller than 10, your code will get stuck in an infinite loop since val will always be smaller than 10.
Hope this helps :)
Answer:
nah im good fam thanks for askin
Explanation:
