How to find the missing length indicated

Based on the markings in the diagram, which conclusion must be true?

Yakvenalex [24]

The correct answer is B) AC = BC
We know this because the two triangles are equal due to SAS

6 0

3 years ago

Read 2 more answers

6 * 2/8 =<br> (Write as a fraction or a mixed number)

Lerok [7]

It would be 3/2 or 1.5

3 0

3 years ago

Read 2 more answers

The formula for the volume V of a cylinder is LaTeX: V=\pi r^2hV = π r 2 h, where r is the radius of the base anThe formula for

Alekssandra [29.7K]

Answer:

$h = \frac{V}{\pi r^2}$

$h = 4 cm$

Step-by-step explanation:

Volume of cylinder is given as $V = \pi r^2 h$

V is the volume the cylinder, r is its radius at the base, while is its height.

To select the formula for h (height) let's make h the subject of the formula as follows:

$V = \pi r^2 h$

$\frac{V}{\pi r^2} = \frac{\pi r^2 h}{\pi r^2}$ (dividing both sides of the equation by $\pi r^2$ )

$\frac{V}{\pi r^2} = h$

$h = \frac{V}{\pi r^2}$

Use the formula above to find the height of the given cylinder where Volume (V) = 36π cm³, and base radius (r) = 3 cm:

$h = \frac{36 \pi}{\pi 3^2}$ (substitution)

$h = \frac{36 \pi}{\pi * 9}$

$h = \frac{36 \pi}{9 \pi}$

$h = \frac{36 \pi}{\pi * 9}$

$h = \frac{36}{9}$ ( $\pi$ cancels $\pi$ )

$h = 4 cm$

8 0

3 years ago

solve the x:(pls help with explanation) 1. 2x/3=18 2. 1.6= x/1.5 3. 14y-8=13 4. 17+6p=9 5. x/3+1= 7/15

Darina [25.2K]

Answer:

1. X=27

2. X=2.4

3. y= 1.5

4. p=-1.33

5. X=-1.6

solution,

$1. \: \: \frac{2x}{3} = 18 \\ \: \: or \: 2x = 18 \times 3(cross \: multiplication) \\ \: \: or \: 2x = 54 \\ \: \: \: or \: x = \frac{54}{2} \\ \: \: \: x = 27$

$2. \: \: 1.6 = \frac{x}{1.5} \\ \: \: or \: x = 1.6 \times 1.5( \: cross \: multiplication) \\ \: \: \: \: x = 2.4$

$3. \: \: 14y - 8 = 13 \\ \: \: \: or \: 14y = 13 + 8 \\ \: \: or \: 14 \: y = 21 \\ \: \: or \: 14 \times y = 21 \\ \: \: \: or \: y = \frac{21}{14} \\ \: divide \: 21 \: and \: 14 \: by \: 7 \: you \: will \: get \\ \:or \: y = \frac{3}{2} \\ y = 1.5$

$4. \: \: 17 + 6p = 9 \\ \: \: or \: 6p = 9 - 17 \\ \: \: or \: 6p = - 8 \\ \: \: or \: p = \frac{ - 8}{6} \\ \: \: or \: p = \frac{ - 4}{3} \\ \: \: p = - 1.33 \\$

$5. \: \: \frac{x}{3} + 1 = \frac{7}{15} \\ \: or \: \frac{x + 1 \times 3}{3} = \frac{7}{15} \\ \: \: or \: \frac{x + 3}{3} = \frac{7}{15} \\ \: or \: 15(x + 3) = 7 \times 3( \: cross \: multiplication) \\ \: \: or \: 15x + 45 = 21 \\ \: \: or \: 15x = 21 - 45 \\ \: \: or \: 15x = - 24 \\ \: \: or \: x = \frac{ - 24}{15} \\ \: divide \: - 24 \: and \: 15 \: by \: 3 \\ \: or \: x = \frac{ - 8}{5} \\ x = - 1.6$

Hope this helps ...

Good luck on your assignment..

3 0

4 years ago

There is a 5% chance that the mean reading speed of a random sample of 2424 second grade students will exceed what value?

zavuch27 [327]

<span>94.1. hope this helps</span>

4 0

4 years ago