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3 years ago

Need help! Will mark Brainiest!

Mathematics

1 answer:

kicyunya [14]3 years ago

5 0

Option B: $y=-\sqrt[3]{x-4}+7$ is the new equation

Explanation:

The given equation is $y=-\sqrt[3]{x}$

We need to find the new graph which is shifted 7 units up and 4 units right.

First, we shall shift the graph 7 units up.

The general formula to shift the graph b units up is given by

$y=f(x)+b$

Thus, to shift the graph 7 units up, let us substitute $b=7$ and $f(x)=-\sqrt[3]{x}$ in the general formula, we have,

$y=$-\sqrt[3]{x}$+7$

Now, we shall shift the graph 4 units right.

The general formula to shift the graph b units right is given by

$y=f(x-b)$

Thus, to shift the graph 4 units right, let us substitute $b=4$ and $f(x)=$-\sqrt[3]{x}+7$$ in the above equation, we have,

$y=-\sqrt[3]{x-4}+7$

Therefore, the new equation is $y=-\sqrt[3]{x-4}+7$

Therefore, Option B is the correct answer.

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Alan has forgotten his 4-digit PIN code.He knows it begins with a 6 and the 4 digits make an even number.How many different sets

Oxana [17]

Answer:

500.

Step-by-step explanation:

The last digit must end with 0, 2, 4, 6, 8 for the Pin code to be even.

The middle 2 digits may be any numbers.

So if the last number is 0 Then there are 10*10 = 100 possible PIN codes.

So as there are 5 possible last digits , the total possible sets of digits

= 5 * 100

= 500.

4 0

3 years ago

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let X = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

3 years ago

For which value of x is xyza a rectangle

lisabon 2012 [21]

Well each angle in a rectangle is 90°, so if x is an angle, it's 90°

I hope that helps!

7 0

4 years ago

If someone type an average of 63 words per minute. how many word can they type in 135 minutes?

Rasek [7]

8505. You would do 63 times 135 to get 8505

7 0

4 years ago

Read 2 more answers

A company surveyed 2,600 North American airline passengers and reported that approximately 75% said that they carry a smartphone

geniusboy [140]

The probability that exactly six out of ten carry a smartphone when travelling is; P(6) = 0.146

The missing part of the question is;

The probability distribution of x is the binomial distribution with n = 10 and p = 0.75.

Calculate P(6)

This is a binomial probability distribution problem that has a general formula as; P(x) = ⁿCₓ × pˣ × q⁽ⁿ ⁻ ˣ⁾

Where;

p is probability of success

q is probability of failure

n is number of experiments

In this question;

n = 10

p = 75% = 0.75

q = 1 - p

q = 1 - 0.75

q = 0.25

Since six passengers are randomly selected, then applying the formula earlier quoted, we have;

P(6) = ¹⁰C₆ × 0.75⁶ × 0.25⁽¹⁰ ⁻ ⁶⁾

P(6) = 0.146

Read more at; brainly.com/question/24239758

4 0

3 years ago