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tamaranim1 [39]
3 years ago
6

Help please. I'm struggling in algebra 1

Mathematics
1 answer:
Stells [14]3 years ago
4 0
The method<span> of solving "by </span>substitution<span>" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.</span>
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Which of the following relations represent a function?
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B
You can only use the same value for x once
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Francine has a picture whose length is its width. She wants to enlarge the picture to have an area of 192 in2. What will the dim
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1. The measures of the length and the width of the picture are equal, so the picture is square shaped.

2. The enlarged picture will still be a square, since when we enlarge, we enlarge all distances with the same factor.

3. Let the dimensions of the large picture be a (length) by a (width)

4. Area of picture = a^{2}=192  in^{2}

a= \sqrt{192} =   \sqrt{16*12}= \sqrt{16*4*3}=4*2* \sqrt{3}=8\sqrt{3} (feet)

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3 years ago
What is the mean mark of 847 ÷ 30?<br>​
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Step-by-step explanation:

8 0
3 years ago
Anyone help me out would mean a lot thank you
topjm [15]

Answer:

It would be D.

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7 0
3 years ago
A (5,3) and B(3,-2) are two fixed points. Find the equation of the locus of P, so that the
andre [41]

Answer:

37=5x-2y,\,1=5x-2y

Step-by-step explanation:

If (x_1,y_1),\,(x_2,y_2),\,(x_3,y_3) are coordinates of a triangle then area of a triangle is equal to \frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|

Let point P be (x,y)

Put (x_1,y_1)=(5,3),\,(x_2,y_2)=(3,-2),\,(x_3,y_3)=(x,y)

Area of a triangle = \frac{1}{2}|5(-2-y)+3(y-3)+x(3+2)|

=\frac{1}{2}|-10-5y+3y-9+5x|\\\\=\frac{1}{2}|-19+5x-2y|

Also,

Area of a triangle = 9 square units

9=\frac{1}{2}|-19+5x-2y|\\\\18=|-19+5x-2y|

±18 = -19 + 5x - 2y

18=-19+5x-2y,\,-18=-19+5x-2y\\\\37=5x-2y,\,1=5x-2y

3 0
3 years ago
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