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Stels [109]
3 years ago
12

Quotient of 213.21 and 15.8. rounded to nearest tenth

Mathematics
2 answers:
lesya692 [45]3 years ago
8 0
Quotient = 213.21 ÷ 15.8 ≈ 13.494

≈ 13.5 to the nearest tenth.
Firlakuza [10]3 years ago
7 0

Answer:

Number would be 13.5

Step-by-step explanation:

Given : quotient of 213.21 and 15.8.

To find : rounded to nearest tenth.

Solution : We have given 213.21 and 15.8.

Quotient of 213.21 and 15.8.

\frac{213.21}{15.8} = 13.49

In 13 .49 we can see the tenth place digit is 4 and smaller digit place is 9 which is greater than 5 so, it would be rounded up tenth place digit would be increased by 1 and other digit become 0

So, number would be 13.5

Therefore, Number would be 13.5

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jenyasd209 [6]
The expression that represents the number of days until only 10% remains is

T((d) 10%) = 100 • (1/2)^3.322
5 0
3 years ago
What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)
kotegsom [21]

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2)  \right )^{2}+\left (6-2  \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.

4 0
3 years ago
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VladimirAG [237]
The large triangle is an isosceles since both angles at the base each equal 42°.
In an isosceles triangle the altitude z is at the same time median , then it bisects the opposite side in the middle . So w = 120/2 = 60

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 tan 42° = (opposite side) / (adjacent side) = z/60
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3 years ago
In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second
Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is (x+3).

The 3rd number is a square of the second. So, the third number is (x+3)^2.

Therefore, the first, second and third numbers are x,(x+3),(x+3)^2 respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

x+(x+3)+(x+3)^2=77

Therefore, the required equation is x+(x+3)+(x+3)^2=77.

d. On simplification, we get

x+x+3+x^2+6x+9=77                   [\because (a+b)^2=a^2+2ab+b^2]

x^2+(6x+x+x)+(3+9)=77

x^2+8x+12=77

Subtract 77 from both sides.

x^2+8x+12-77=77-77

x^2+8x-65=0

Therefore, the simplified form of the required equation is x^2+8x-65=0.

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3 years ago
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