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Anuta_ua [19.1K]
3 years ago
14

What is y = tan θ when θ = −45°?

Mathematics
2 answers:
levacccp [35]3 years ago
6 0

Answer:

1

Step-by-step explanation:

Dvinal [7]3 years ago
3 0

Answer:

The answer on edge is -1

Step-by-step explanation:

I just took the test

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The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
3 years ago
All of the functions shown below are either exponential growth or decay functions.
AlekseyPX

Answer:

Step-by-step explanation:

If an exponential function is in the form of y = a(b)ˣ,

a = Initial quantity

b = Growth factor

x = Duration

Condition for exponential growth → b > 1

Condition for exponential decay → 0 < b < 1

Now we ca apply this condition in the given functions,

1). y=3.2(1+0.45)^{2x}

   Here, (1 + 0.45) = 1.45 > 1

   Therefore, It's an exponential growth.

2). y=(0.85)^{3x}

    Here, (0.85) is between 0 and 1,

    Therefore, it's an exponential decay.

3). y = (1 - 0.03)ˣ + 4

    Here, (1 - 0.03) = 0.97

    And 0 < 0.97 < 1

    Therefore, It's an exponential decay.

4). y = 0.5(1.2)ˣ + 2

    Here, 1.2 > 1

    Therefore, it's an exponential growth.

5 0
2 years ago
How are numbers related?
MAVERICK [17]
<span> <span>two numbers are related in this way:
the number 1 is subtracted from the first number, the difference is squared, then doubled;the result is equal to the second number. the number 1 is added to the first number, and the sum is squared;the result is equal to 4 minus the second number. determine the numbers. </span></span>
3 0
3 years ago
Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th
dexar [7]

Answer:

The labor fee is $14.25, each quart of oil costs $2.25.

Step-by-step explanation:

Let $x be thee price of each quart of oil and $y be a flat fee for labor.

1. If the oil change for one car required 5 quarts of oil, then these 5 quarts cost $5x and together with a flat fee for labor it cost $25.50. Thus,

5x+y=25.50.

2. If the oil change for another car required 7 quarts of oil, then these 7 quarts cost $7x and together with a flat fee for labor it cost $30.00. Thus,

7x+y=30.00.

3. Subtract from the second equation the first one, then

7x+y-(5x+y)=30.00-25.50,\\ \\7x+y-5x-y=4.50,\\ \\2x=4.50,\\ \\x=\$2.25.

Substitute it into the first equation:

5\cdot 2.25+y=25.50,\\ \\y=25.50-11.25,\\ \\y=\$14.25.

The labor fee is $14.25, each quart of oil costs $2.25.

6 0
2 years ago
Plss can someone help me
GenaCL600 [577]
I got the answer isa D mate
8 0
3 years ago
Read 2 more answers
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