Answer:
40/3; 13.3333333333333
Step-by-step explanation:
The volume of the cone is:
(1/3)(pi)(r^2)(h) =
(1/3)(pi)(10^2)(10) =
1000pi/3
The volume of the cylinder is:
(pi)(r^2)(h) =
(pi)(5^2)(h) =
25pi(h) = 1000pi/3 -->
pi(h) = 40pi/3 -->
h = 40/3
Split up each force into horizontal and vertical components.
• 300 N at N30°E :
(300 N) (cos(30°) i + sin(30°) j)
• 400 N at N60°E :
(400 N) (cos(60°) i + sin(60°) j)
• 500 N at N80°E :
(500 N) (cos(80°) i + sin(80°) j)
The resultant force is the sum of these forces,
∑ F = (300 cos(30°) + 400 cos(60°) + 500 cos(80°)) i
… … … + (300 sin(30°) + 400 sin(60°) + 500 sin(80°)) j N
∑ F ≈ (546.632 i + 988.814 j) N
so ∑ F has a magnitude of approximately 1129.85 N and points in the direction of approximately N61.0655°E.
Nothing else is given, so for the two triangles to be congruent, the only possible proof is the ASA theorem.
first pairs of angles: 2x+7=x+21 => x=14
second pairs of angles: 8y-4=4y+28 =>y=8
The two triangles share the same side PR
Based on the Angle-Side-Angle Triangle Congruence theorem, these two triangles are congruent with x=14, y=8
(2x+7) +(8y-4) +Q=180 =>85
Answer:
Step-by-step explanation:
-0.25
-1/3
1/4
0.3
The answer is B. There can not be any alike "x" inputs.
