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NemiM [27]
3 years ago
15

Two separate bacteria populations grow each month and are represented by the functions f(x) = 3x and g(x) = 7x + 6. In what mont

h is the f(x) population greater than the g(x) population?
Month 1
Month 2
Month 3
Month 4
Mathematics
1 answer:
MAXImum [283]3 years ago
8 0

Answer:

The f(x) population will never be more than the g(x) population with the given equations.

Step-by-step explanation:

Due to the fact that we have 7x in the g(x) equation and only 3x in the f(x) equation, then we know that every month, the g(x) gets larger than the f(x) by 4. Therefore, the f(x) equation will never catch the g(x) equation.

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How many different simple random samples of size 5 cab be obtained from a population whose size is 46
otez555 [7]

Answer:

1370754

Step-by-step explanation:

From what I can see, you are probably studying combinations and permutations at the moment. Since this is a question about how many groups of five can be produced from a sample size of 46, the groups are random and not in order, which may rule for us to use the combination formula.

Once you compute this, this answer is basically saying that 1370754 groups of 5 can be created from a sample size of 46

8 0
4 years ago
Find f(-2) if f(x)=-x^3+2x^2+x-1
ser-zykov [4K]

Answer:

f(- 2) = 13

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x)

f(- 2) = - (- 2)³ + 2(- 2)² + (- 2) - 1

        = - (- 8) + 2(4) - 2 - 1 = 8 + 8 - 2 - 1 = 13

3 0
3 years ago
The sum of the measures of the angles of any triangle is 180 degrees. in triangle​ abc, angles a and b have the same​ measure, w
frutty [35]
<span>Its given that the sum of the values of total angles of a triangle is 180. It is also given that angles a and b are equal and that value of c is 72. Thus we get the following equation:
   
a + b + c = 180
   
a + a + 72 = 180 since a = b

2a = 108
   
a = b = 54 and c = 72</span>
7 0
3 years ago
What is the highest fraction here -3/25, -7 / 20, -27 / 50, -13 / 20, 16 / 25, 53 / 100, -1 / 3​
galina1969 [7]
16/25 is the highest, because if you multiply it by four you get 64/100, and the rest of the fractions are negative.
7 0
4 years ago
Indefinite integral need help pleaseeeeeee
tatiyna
Integrate indefinite integral:
I=\int\frac{dx}{e^{2x}+3e^x+2}dx

Solution:
1. use substitution u=e^x 
=>
du=e^xdx
=>
dx=\frac{du}{e^x}
=>
dx=\frac{du}{u}
=>
I=\int\frac{du}{u(u^2+3u+2)}du
=\int\frac{du}{u(u+2)(u+1)}du
2. decompose into partial fractions
\frac{1}{u(u+2)(u+1)}
=\frac{A}{u}+\frac{B}{u+2}+\frac{C}{u+1}
where A=1/2, B=1/2, C=-1
=\frac{1}{2u}+\frac{1}{2(u+2)}-\frac{1}{u+1}
3. Substitute partial fractions and continue
I=\int\frac{du}{2u}+\int\frac{du}{2(u+2)}-\int\frac{du}{u+1}
=\frac{log(u)}{2}+\frac{log(u+2)}{2}-log(u+1)}
4. back-substitute u=e^x
=\frac{log(e^x)}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}
=\frac{x}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}

Note: log(x) stands for natural log, and NOT log10(x)

7 0
3 years ago
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