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soldi70 [24.7K]
3 years ago
10

Marty drew a model of the school library. The total area of the floor is 132 square

Mathematics
1 answer:
motikmotik3 years ago
8 0

Answer:

Step-by-step explanatio11n:

116

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Tcecarenko [31]
It’s an integer, rational number, and a whole number
7 0
3 years ago
Item 18
Nimfa-mama [501]

A mixed number in simplest form, in the box is 40  5/8 cm^3.

We have given that,

The figure contains a right rectangular prism. The length of the prism is labeled 6 and one-half centimeters, the width is labeled 2 and one-half centimeters, and the height is labeled 2 and one-half centimeters.

<h3>What is the volume of the prism?</h3>

The figure is a rectangular prism, so the formula would be Volume = length x width x height.

length = 6 .5cm

width  =  2.5cm

height  =  2.5cm

If you plug everything you have in the problem into the volume equation, you would get

volume = 6.5cm x 2.5cm x 2.5 cm.

Without a calculator first, turn the mixed numbers into improper fractions.

6 .5=13/2

2.5 = 5/2

Volume = 13/2  x 5/2   x 5/2

When you multiply everything together you should get.

As a mixed number, that would be 40 5/8.

To learn more about the prism visit:

brainly.com/question/23963432

#SPJ1

7 0
2 years ago
If (×+1 ) and(×+2) are factors of the expressionx^4+ax^2+b , find the value of and b, with these value of and factorize complete
kherson [118]

Answer:

Step-by-step explanation:

(x⁴+ax²+b) ÷ (x+1) = x³-x²+(a+1)x-(a+1) remainder b+(a+1)

Since x+1 is a factor, b+(a+1) = 0.

(x³-x²+(a+1)x-(a+1)) ÷ (x+2) = x²-3x+(a+7) remainder -3a-15

Since x+2 is a factor, -3a-15 = 0

a = -5

b = 4

x⁴+ax²+b = x⁴ - 5x² + 4 = (x²-4)(x²-1) = (x+2)(x-2)(x+1)(x-1)

7 0
3 years ago
What is the slope of the line??
Semmy [17]

Answer:

sorry for being late  :/

Step-by-step explanation:

slope , m = 1/3  

3 0
3 years ago
Find the equations of the tangents to the curve y = x²-x-12 at each of the points where the curve crosses the x-axis.​
poizon [28]

Step-by-step explanation:

First, find the zeroes of the parabola

{x}^{2}  - x - 12

{x}^{2}  - 4x + 3x - 12

x(x  - 4) + 3(x - 4)

(x +  3)(x  - 4) = 0

x =  - 3

x - 4 = 0

x = 4

So the zeroes or where the curve crosses the x axis is at 4 and -3.

Now, we take the derivative of the function.

\frac{d}{dx} ( {x}^{2}  - x - 12) = 2x - 1

Plug in -3, and 4 into the derivative function

2( - 3) =  - 7

2(4) - 1 = 7

So at x=-3, our slope of the tangent line is -7 and must pass through (-3,0). So we use point slope formula.

y - y _{1} = m(x - x _{1})

y - 0 =  - 7(x - (  - 3)

y =  - 7x - 21

At x=4, our slope of tangent line is 7, and pass through (4,0) so

y - 0 = 7(x - 4)

y = 7x - 28

So the equations of tangent is

y =  - 7x - 21

y = 7x - 28

6 0
2 years ago
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