Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)
we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>
step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3
the midpoint AB is (3√2,2√3)
the answer isthe abscissa of the midpoint of the line segment is 3√2
see the attached figure
I would go withhh c but I am not 100% sure
Answer:
x=-2
Step-by-step explanation:
-4x - 8 = -4 • (x + 2)
Answer:
The solution of the system is (6, 9).
Step-by-step explanation:
Solve one of the variables and substitute the answer for the other variable.
Select one of the problems and solve for x.
3x+y=27
Subtract y from both sides.
3x+-y=27
Divide both sides by three.
x=1/3(-y + 27)
Multiply 1/3 by -y + 27.
x = -1/3y + 9
Replace -y/3 + 9 for x in the other problem 3x-2y=0.
3(-1/3y + 9) - 2y = 0
Multiply 3 by -y/3 + 9.
−y+27−2y=0
Add -y to -2y.
−3y+27=0
Subtract 27 from both sides of the problem.
−3y=−27
Divide both sides by −3.
y=9
Replace 9 for y in x=−1/3y+9.
x=−1/3*9+9
Multiply −1/3 times 9.
x=-3+9
Add 9 to -3.
x = 6.
x = 6, y = 9.
The answer is 3 if you add 2 into 1 you get 3