Answer: ![\dfrac{3}{26}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B26%7D)
Step-by-step explanation:
Given: The number of green balls in bag =6
Total number of balls = ![3+6+3+1=13](https://tex.z-dn.net/?f=3%2B6%2B3%2B1%3D13)
The probability of drawing first ball is green is given by :-
![P(G)=\dfrac{6}{13}](https://tex.z-dn.net/?f=P%28G%29%3D%5Cdfrac%7B6%7D%7B13%7D)
Since he didin't replace first ball, then the total number of remains = 12
The number of blue balls in the bag = 3
The probability of drawing second ball is blue is given by :-
![P(B)=\dfrac{3}{12}](https://tex.z-dn.net/?f=P%28B%29%3D%5Cdfrac%7B3%7D%7B12%7D)
Now, the probability that the juggler first draws a green ball followed by a blue ball is given by :-
![P(G)\times P(B)=\dfrac{6}{13}\times\dfrac{3}{12}=\dfrac{3}{26}](https://tex.z-dn.net/?f=P%28G%29%5Ctimes%20P%28B%29%3D%5Cdfrac%7B6%7D%7B13%7D%5Ctimes%5Cdfrac%7B3%7D%7B12%7D%3D%5Cdfrac%7B3%7D%7B26%7D)
The probability that the juggler first draws a green ball followed by a blue ball : ![\dfrac{3}{26}](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B26%7D)