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Leni [432]
3 years ago
11

????????????????????????

Mathematics
1 answer:
Otrada [13]3 years ago
8 0
I would never know the answer to this question
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Can I please get help with this I give thanks
gladu [14]
First one :
We divide it into two rectangles (the top one has dimensions 2in*4in)

The area of the top rectangle is 2*4=8 in^2

The second rectangle has dimensions 3*(5-3)=6 in^2
Hence the total area is 8+6=14 square inches

Second one :

We divide it into a rectangle (dimensions 11*17) and a triangle on the top.

The area of the rectangle is 11*17=187 m^2
The rectangle has dimensions 17 (base's length) and 23-11 (height) hence its area is 17*(23-11)/2=102 m^2

Hence the total area is 102+187=289 square meters

6 0
2 years ago
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What is 6/15 written as a decimal?
Allushta [10]
It will be C cause you divid 15 and 6
3 0
3 years ago
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The coordinates of vertex A of ABC are
topjm [15]
Yeah uh show us a photo of the equation
4 0
2 years ago
Write sin 29 degrees 32 minutes in terms of it cofunction
12345 [234]

Answer:

Sin 29° 32' = Cos 60° 28'

Step-by-step explanation:

Here in this problem, we have to write Sin 29° 32' in terms of its co-function.

We know that co-function of Sin Ф = Cos ( 90° - Ф ).

Therefore, we have to find a complementary angle of 29° 32'.

So, ( 90° - 29° 32' ) = 60° 28'

Therefore, Sin 29° 32' = Cos 60° 28' ( Answer )

5 0
3 years ago
An engineering school reports that 53% of its students were male (M), 35% of its students were between the ages of 18 and 20 (A)
erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

                      18-20                  Not 18-20           Total

Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) =  0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

3 0
3 years ago
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