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Ludmilka [50]
3 years ago
5

Solve for y: y+5x=6;x= -1,0,1

Mathematics
2 answers:
AlekseyPX3 years ago
7 0
When x = -1

y + 5x = 6

y = 6 - 5x

y = 6 - (5)(-1)

y = 6 - (-5)

y = 11

when x = 0

y = 6 - 5x

y = 6 - (5)(0)

y = 6 - 0

y = 6

when x = 1

y = 6 - 5x

y = 6 - (5)(1)

y = 6 - 5

y = 1
DanielleElmas [232]3 years ago
3 0
X=101 and Y= 511 that's my answer
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Select the correct answer.
Digiron [165]

Answer:

4/3

Step-by-step explanation:

Given function = p(x) = (6x-4)/x

First we will calculate p(1) and p(3)

p(1) = (6(1) - 4)/1 = 6-4 = 2

p(3) = (6(3) - 4)/3 = (18-4)/3 = 14/3

Rate of change on interval [1,3] = [p(3) - p(1)]/(3-1)

=> (14/3 -2)/(2)

=> (14-6)/(3*2)

=> 8/6

=> 4/3

So average rate of change is 4/3

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3 years ago
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kolbaska11 [484]

Answer:

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3 0
3 years ago
Again, simple questions! asap help please! <br> 15 points!
poizon [28]

Answer:

3) r = 1.5

7) y = 18

11) x = -10

Step-by-step explanation:

3) Isolate the variable by dividing each side by factors that don't contain the variable.

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6 0
2 years ago
How do you know where to put the constant when finding general solutions for differential equations?
Norma-Jean [14]
Let's suppose we want to solve y'=y with y(0)=2. Separating variables and integrating, we get

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Leaving the solution in this form, the initial condition gives

2=e^{0+C}=e^C\implies C=\ln2

This means the solution is y=e^{x+\ln2}.

Now if we were to write y=e^{x+C}=e^xe^C=Ce^x, then we would have found

2=Ce^0\implies C=2

so that the solution would have been y=2e^x.

But these two solutions are the same, since y=e^{x+\ln2}=e^xe^{\ln2}=2e^x. So we get the same solution regardless of where we place C, despite getting different values for C.
5 0
3 years ago
Choose the best estimate for the capacity of a water bottle that is 8 inches tall.
labwork [276]

my answer here would be B)

5 0
3 years ago
Read 2 more answers
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