All categories

3 years ago

Enter an inequality that represents the graph in the box.

Mathematics

1 answer:

Yuliya22 [10]3 years ago

7 0

Find 2 points on the line:

We will use (2,2) and (0,-6)

Find the slope of the line which is the change in Y over the change in X:

(-6-2) / (0-2) = -8/-2 = 4

The slope = 4

Find the Y intercept:

y = 4x+b

use y1 for y and x1 for x

2 = 4(2) +b

2 = 8 +b

Subtract 8 from both side:

b = -6

Now you have the slope (4) and Y intercept (-6)

The equation of the line becomes y = 4X-6

The line is solid and the shaded portion of the graph is to the left of the line and it is a positive slope so the inequality would become

y ≥ 4x -6

You might be interested in

There are 24 boys and 16 grils on a playground. What is the ratio of boys tototal number of children on the playground

tatuchka [14]

Answer:

24:40 or 3:5

Step-by-step explanation:

Boys: 24

All children: 24 + 16 = 40

Boys to total amount of children: 24:40

Simplify: 24:40 = 3:5

8 0

3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

6 0

3 years ago

Read 2 more answers

Am I correct? If not please explain why!

Kipish [7]

yes, you are correct. every input corresponds to only one output

6 0

3 years ago

a card is chosen from a standard deck, then a month of the year is chosen. find the probability of getting a face card and june

Irina-Kira [14]

Answer:

Probability of chossing a face card and the month of june = 0.019

Step-by-step explanation:

Let A be the event that a face card is chosen from a deck of 52 cards

And

B be the event that a month is being chosen from 12 months of an year

So,

n(S)for A=52

n(S)for B=12

As a deck of card has total of 12 face cards so

P(A)=12/52

=3/13

P(B)=1/12

As both the events are independent, the probability of A and B is the product of both events’ probabilities.

P(A and B)= P(A)*P(B)

=3/13*1/12

=3/156

=0.019

4 0

3 years ago

"if z is a standard normal variable, find the probability. the probability that z lies between 0 and 3.01"

spayn [35]

Probability between z = 0 and z = 3.01 is given by

P(0<z<3.01) = P(z<3.01) - P(z<0)

Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987

Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987

5 0

3 years ago