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3 years ago

Which is greater 0.7 or 3/4

2 answers:

6 0

The answer is 3/4 because 0.7= 7/10. To have the same denominator, multiply the fraction by the other denominator. ( 4 is the denominator of the other fraction.) 7x4=28 10x4=40 so it's equal 28/40
Do the same thing for the other fraction. ( 10 is the denominator.)
3x10=30 4x10=40 so it's equal 30/40
We have the same denominator now so we can just compare it.
28/40 < 30/40

vovangra [49]3 years ago

3 0

0.7 can be turned into a fraction which can be 70/100 and 3/4 can be turned into 75/100 so 3/4 would be greater

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9 1/2 divided by 3 7/10

OleMash [197]

Solution:

Convert the fractions into improper fractions and solve.

9 1/2 ÷ 3 7/10
=> 19/2 ÷ 37/10
=> 19/2 x 10/37
=> 19 x 5/37
=> 95/37

Convert the fraction into mixed fraction (Not required):

=> 95/37 = 37/37 + 37/37 + 21/37
=> 1 + 1 + 21/37
=> 2 + 21/37
=> 2 21/37

The solution to the problem is 2 21/37.

8 0

2 years ago

Read 2 more answers

2.Solve the following quadratic equations i. 9x^2 - 1/16 ii. 2h^2 - 3h - 27

Juli2301 [7.4K]

$i)~9x^2-\dfrac{1}{16}=0\iff9x^2=\dfrac{1}{16}\iff x^2=\dfrac{1}{9\cdot16}\iff \\\\x^2=\dfrac{1}{144}\iff x=\pm\sqrt{\dfrac{1}{144}}=\pm\dfrac{1}{12}\Longrightarrow\boxed{x=\pm\dfrac{1}{12}}$

$ii)~2h^2-3h-27=0\\\\\Delta=b^2-4ac\to \Delta=(-3)^2-4\cdot2\cdot(-27)\to\Delta=9+216=225\\\\
\Longrightarrow h=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-(-3)\pm\sqrt{225}}{2\cdot2}=\dfrac{3\pm15}{4}\\\\\begin{cases}h_1=\dfrac{3+15}{4}=\dfrac{18}{4}\iff \boxed{h_1=\dfrac{9}{2}}\\h_2=\dfrac{3-15}{4}=\dfrac{-12}{4}\iff\boxed{h_2=-3}\end{cases}$

4 0

3 years ago

Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral

Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

$l_{AB} = \sqrt{\left (6-4 \right )^{2}+\left (6-1 \right )^{2}} = \sqrt{29}$

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

$l_{BC} = \sqrt{\left (1-6 \right )^{2}+\left (4-6 \right )^{2}} = \sqrt{29}$

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

$l_{CD} = \sqrt{\left (-1-1 \right )^{2}+\left (-1-4 \right )^{2}} = \sqrt{29}$

The length of side DA, with D = (-1, -1) and A = (1,4) gives;

$l_{DA} = \sqrt{\left (4-(-1) \right )^{2}+\left (1-(-1) \right )^{2}} = \sqrt{29}$

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Therefore;

$Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1$

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

$Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1$

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

5 0

3 years ago

Solve 4y-1=7 plz step by step

miv72 [106K]

Hi,

Here we are going to be working on isolating the variable y, and seeing what its value equates to.

To do this, we must try and get the variable y on one side of the equation by itself.

Let's look at step one -

4y - 1 = 7

We want to get rid of the 1 since we need to isolate x. We do this by doing the inverse of its operation. Since 1 is negative, if we add positive 1 to it - we will get 0, thereby being closer to isolating y.

However, when we do something on one side of the equation we must do it on the other. This means we will add 1 on both sides.

4y - 1 + 1 = 7 + 1

4y = 8

Remember how I mentioned we do the inverse of the operation? In this case, 4 is multiplying y. The inverse operation of multiplication is division. So, to get rid of the 4 - we must divide 4y by 4, on both sides.

4y / 4 = 8 / 4

y = 2

We now know the variable y is equal to 2.

Hopefully, this helps.

3 0

4 years ago

Read 2 more answers

James invests $5,072 in a savings account

Sergeu [11.5K]

Answer:

$13087.92

Step-by-step explanation:

formula: ab^x

a= starting amount

a= 5072

b= 1+r

r=rate

r=9%=0.09

b=1+0.09 =1.09

x= 11 (years)

account after 11 years:

= 5072(1.09)^11

=13087.9227277

= 13087.92

5 0

3 years ago