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3 years ago

How do I multiply fractions

Mathematics

1 answer:

Naddika [18.5K]3 years ago

7 0

Just multiply directly numerator with numerator and denominator with denominator

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Mrs. Bergstedt teaches six classes. In her first period class she has 19 students, her third period she has 13 students, her fou

PilotLPTM [1.2K]

We find the average by adding up all the students and dividing them by the number of classes she has. 19 + 13 + 19 + 9 + 14 + 15 is 89, and that divided by 6 is approximately 14.8, rounded to the nearest tenth.
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Hope this helps!

3 0

3 years ago

Read 2 more answers

Paulo has $145 in his savings account. He earns $36 a week moving lawns. If Paulo saves all of his earnings, after how Many week

kondor19780726 [428]

Answer:

433-145=288

288/36=8

answer=8

Step-by-step explanation:

6 0

3 years ago

Which numerical pattern is linear?

Anna35 [415]

Step-by-step explanation:

I believe the answer is A and B

4 0

2 years ago

1) find the equation of the line parallel to

In-s [12.5K]

<u>Answer:</u>

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

<u>Solution:</u>

<u><em>1) find the equation of the line parallel to x-5y=6 and through (4,-2).</em></u>

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

<u><em> 2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)</em></u>

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

4 0

2 years ago

What is the equation in slope-intercept form of a line (y = mx + b) that has aslope of 3 y-intercept of 6?

arsen [322]

The equation of the line is y = 3x + 6

<h3>What are linear equations?</h3>

Linear equations are equations that have constant average rates of change.

Note that the constant average rates of change can also be regarded as the slope or the gradient

<h3>How to determine the equation of the line?</h3>

The given parameters are

Slope, m = 3

y-intercept, c = 6

A linear equation is represented as

y = slope * x + y-intercept

i.e.

y = mx + c

So, we have

y = 3x + 6

Hence. the linear equation is y = 3x + 6