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3 years ago

Determine whether the triangles are congruent by AA., SSS, SAS, or not similar.

Mathematics

1 answer:

klemol [59]3 years ago

6 0

Step-by-step explanation:

they are similar by AA .

plz mark my answer as brainlist plzzzz . hope this will be helpful to you.

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Number 19 help due in 2 minutes

amm1812

Answer: 4 bags of plates plates 3 bags of cups 2 bags of forks

Step-by-step explanation:

48+48=96 32+32+32=96 24+24+24+24=96

7 0

4 years ago

A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular

Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is $A=18\sqrt{3}\ units^2$

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

$m\angle AOM =30^o$

In the right triangle OAM

$tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}$

$\frac{a}{2r}=\frac{\sqrt{3}}{3}$

we have

$r=3\ units$

substitute

$\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units$

Find the area of six equilateral triangles

$A=6[\frac{1}{2}(r)(a)]$

simplify

$A=3(r)(a)$

we have

$r=3\ units\\a=2\sqrt{3}\ units$

substitute

$A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2$

Therefore

The approximate are of the inscribed disk using the regular hexagon is $A=18\sqrt{3}\ units^2$

6 0

3 years ago

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 5 to 3 . If there were

dlinn [17]

$\bf \begin{array}{ccll} yes&no\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 5&3\\ y&2829 \end{array}\implies \cfrac{5}{y}=\cfrac{3}{2829}\implies \cfrac{5\cdot 2829}{3}=y\implies 4715=y \\\\\\ \stackrel{\textit{total number of votes}}{yes+no}\implies 4715+2829\implies 7544$

5 0

3 years ago

The rate of planting the grass is ` x per square meter. Find the cost of planting the grass on a

kotegsom [21]

Step1: Find the area of the triangular lawn

Given, base of the triangle is y metres and the height is z metres

Area of the triangle =

× base × height

Therefore, area of the triangular lawn =

yz metre

Step 2:Find the cost of planting the grass

Rate of planting the grass is Rs. x per square metre.

Therefore, the cost of planting the grass on a triangular lawn =cost per square meter × area of the triangular lawn

=x×

yz=

xyz

Hence, the cost of planting the grass on a triangular lawn whose base is y metres and height is z metres is Rs.

x y z.

Step-by-step explanation:

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2 years ago

There are 3/20 tickets left to sell and capacity is 3000 how many tickets are available to sell

Musya8 [376]

Answer:

Step-by-step explanation

20x = 900

----- -------

20 20

5 0

3 years ago