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stellarik [79]
4 years ago
7

If (x)=3x-1 and s(x)=2x+1, which expression is equivalent to r over s (6) ?

Mathematics
1 answer:
galina1969 [7]4 years ago
7 0

Answer:

\frac{3(6)-1}{2(6)+1}

Step-by-step explanation:

we have

r(x)=3x-1

s(x)=2x+1

so

\frac{r}{s}(x)=\frac{r(x)}{s(x)}=\frac{3x-1}{2x+1}

substitute the value of x=6 in the expression

\frac{r}{s}(6)=\frac{3(6)-1}{2(6)+1}=\frac{17}{13}

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