Answer:
Here,
x + 25° + 3x + 95° + 80°=360° (Sum of angles of a quadrilateral is 360°)
or,x+3x + 25° + 95° + 80° =360°
or,4x + 200 = 360°
or,4x = 360 - 200
or,4x = 160
or,x = 160÷4
or,x = 40
Now,
Angle K = (x + 25)° = 40 + 25° = 65°
Angle L = 3x° = 3 × 40° = 120°
If you factored this the outcome would be,
(q+3)(3p^2-4)
8(14-9)+5
________
2
3. + 6
8(5)+5
______
9 + 6
40 + 5
————
15
45
____
15
= 3
u-94=0
u=94
because -2 and -2 will reduced
First, you need to rewrite the expression into binomial form, so you are working with two terms (as you world with a quadratic):
(x²)²-3(x²)-4=0
Now, you can place the x²s into brackets as the coefficient is now 1:
(x² )(x² )
Next, find out two numbers that add together to give you -3 and multiply to give -4 (these are the leftover integers after removing the x²s). These two numbers are -4 and 1.
Place the -4 and 1 into the brackets:
(x²-4)(x²+1)=0
Notice that the x²-4 is a difference of two squares, so can be further factorised into (x+2)(x-2)
This leaves you with a final factorisation of:
(x+2)(x-2)(x²+1)=0
Now we handle each bracket individually to obtain our four solutions for x:
x+2=0
x=-2
x-2=0
x=2
x²+1=0
x²=1
x=<span>±1</span>
