Answer:- | -7 + 4 |
= - | -3 | Since | -3 | = 3:
= - (3)
= - 3
Answer:
Linear correlation exists
Step-by-step explanation:
Given the data :
X : | 2 4 5 6
Y : | 6 9 8 10
Using technology to fit the data and obtain the correlation Coefficient of the regression model,
The Correlation Coefficient, r is 0.886
To test if there exists a linear correlation :
Test statistic :
T = r / √(1 - r²) / (n - 2)
n = number of observations
T = 0.886 / √(1 - 0.886²) / (4 - 2)
T = 0.866 / 0.3535845
T = 2.449
Comparing Pvalue with α
If Pvalue < α ; Reject H0
Pvalue = 0.1143
α = 0.05
Pvalue > α ; We reject the null and conclude that linear correlation exists
Answer:
Range: [-2, 2] {y | -2 ≤ y ≤ 2}
Step-by-step explanation:
The given function is y = 2sinx
We have to find the range of the given function.
Since at y-axis sine function has the variance between -1 to 1 so range of y = sinx is [-1, 1]
and if the amplitude of sine function is 2 then sine function will vary from -2 to 2 which implies that range of y = 2 sinx will be [-2, 2]
So range of y = 2sinx is [-2, 2]
1x+ 3y = -12x + 2y = 6
+12x +12x
13x + 3y = 2y = 6
+3y +3y
13x = 5y = 6
13x = 5y and 5y = 6
