The plasma membrane needs lipids, which make a semi-permeable barrier between the cell and its environment. It also needs proteins, which are involved in cross-membrane transport and cell communication, and carbohydrates, which decorate both the proteins and lipids and help cells recognize each other. Hope this helps :)
Answer:
<h2>RrYy and rryy
</h2>
Explanation:
1. As given; Round seeds (R) are dominant on wrinkled seeds (r),
Yellow seeds (Y) are dominant on green seeds (g).
In a testcross, between an unknown genotype and a homozygous recessive with wrinkled and green seeds (rryy).
offspring are:
Round and yellow are 53; genotype (R_Y_)
round and green are 49; genotype (R_yy)
wrinkle and yellow are 44; genotype (rrY_)
wrinkled and green are 51 ; genotype (rryy)
Here, the genotype of parents of these offspring would be RrYy and rryy.
Answer:
breathing and leg exercises
Explanation:
Based on the information provided within the question it can be said that the most appropriate to include in the client's postoperative plan of care would be to make sure complete their deep breathing and leg exercises. This is because after these surgeries the individual will be on bed rest, thus limiting their activity and putting them at risk for respiratory problems as well as deep vein thrombosis. Therefore doing these exercises will help prevent these complications.
No map can accurately and proportionally represent every country’s size in proportion to another. For example, most maps the USA shows Texas as the largest states, but on a globe, Alaska is by far bigger. Hope this helps!
Answer:
42,5 mL
Explanation:
We need to use the serial dilution formula beacuse we start with a stock concentrate solution and we need to prepare a new less concentrated one.
<u>DF in the dilution factor, Vi is the initial volume and Vf is the final volume.</u>
The first step is to have the same measurment unit so we need to convert 345 µg to mg.
we know that 1 µg equals 0,001 g, hence:
now the final volume is 0,345 mg protein/ mL and the inital volume is 15mg protein/mL, both of them are in the same unit so we can use the formula
Now since the question said that we already have 1.0mL of the amylase stock solution we need to subtract that 1.0mL to the 43,5 mg protein/mL
So, we need 42,5 mL of diluting buffer if we want a final concentration of 345 µg protein/mL (0.345 mg protein/mL)
