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Marysya12 [62]
3 years ago
15

A direct variation function contains the points (–8, –6) and (12, 9). Which equation represents the function?

Mathematics
2 answers:
vodomira [7]3 years ago
8 0

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form \frac{y}{x}=k or y=kx

<u>With the point 1 or the point 2 find the value of the constant k</u>

<u>Point 1</u> (-8,-6)

x=-8

y=-6

substitute

\frac{y}{x}=k

\frac{-6}{-8}=k

k=\frac{3}{4}

therefore

the equation is

y=\frac{3}{4}x

<u>the answer is the option </u>

y=\frac{3}{4}x

strojnjashka [21]3 years ago
6 0
Y=3/4x, as the sign of the function does not change, and the y value is less than the x value
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Verify that (cos²a) (2 + tan² a) = 2 - sin² a....<br>​
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Trigonometric Formula's:

\boxed{\sf \ \sf \sin^2 \theta + \cos^2 \theta = 1}

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Given to verify the following:

\bf (cos^2a) (2 + tan^2 a) = 2 - sin^2 a

\texttt{\underline{rewrite the equation}:}

\rightarrow \sf (cos^2a) (2 + \dfrac{sin^2 a}{cos^2 a} )

\texttt{\underline{apply distributive method}:}

\rightarrow \sf 2 (cos^2a) + (\dfrac{sin^2 a}{cos^2 a} ) (cos^2a)

\texttt{\underline{simplify the following}:}

\rightarrow \sf 2cos^2 a  + sin^2 a

\texttt{\underline{rewrite the equation}:}

\rightarrow \sf 2(1 - sin^2a )  + sin^2 a

\texttt{\underline{distribute inside the parenthesis}:}

\rightarrow \sf 2 - 2sin^2a   + sin^2 a

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2 years ago
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Solve for x. 5(x – 10) = 30 – 15x
SIZIF [17.4K]
Hey!


The first step to solving this problem would be to distribute the parenthesis. We do this so that we can get rid of the parenthesis.

<em>Original Equation :</em>
5 ( x - 10 ) = 30 - 15x

<em>New Equation {Changed by Distribution} :</em>
5x - 50 = 30 - 15x

The next step would be to 50 to both sides. The reason we do that is to get rid of the 50 that is on the left side of the equation.

<em>Old Equation :</em>
5x - 50 = 30 - 15x

<em>New Equation {Changed by Adding 50 to Both Sides} :</em>
5x = 80 - 15x

And now we would add 15x to both sides to get rid of the -15x on the right side of the equation.

<em>Old Equation :</em>
5x = 80 - 15x

<em>New Equation {Changed by Adding 15x to Both Sides} :</em>
20x = 80

Now we divide both sides by 20 to get x on it's own.

<em>Old Equation :</em>
20x = 80

<em>New Equation {Changed by Dividing Both Sides by 20} :</em>
\frac{20x}{20} = \frac{80}{20}

Finally, all we have to do is solve to find x.

<em>Old Equation :</em>
\frac{20x}{20} = \frac{80}{20}

<em>Solution {Old Equation Solved} :</em>
x = 4

<em>So, in the equation </em><span><em>5 ( x – 10 ) = 30 – 15x</em>,  x = 4.

Hope this helps!


- Lindsey Frazier ♥</span>
3 0
3 years ago
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