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Marysya12 [62]
3 years ago
15

A direct variation function contains the points (–8, –6) and (12, 9). Which equation represents the function?

Mathematics
2 answers:
vodomira [7]3 years ago
8 0

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form \frac{y}{x}=k or y=kx

<u>With the point 1 or the point 2 find the value of the constant k</u>

<u>Point 1</u> (-8,-6)

x=-8

y=-6

substitute

\frac{y}{x}=k

\frac{-6}{-8}=k

k=\frac{3}{4}

therefore

the equation is

y=\frac{3}{4}x

<u>the answer is the option </u>

y=\frac{3}{4}x

strojnjashka [21]3 years ago
6 0
Y=3/4x, as the sign of the function does not change, and the y value is less than the x value
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Add.
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Multiply.
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6 0
3 years ago
Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)
kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios  between two points (x1,f(x1)) and (x2,f(x2)) is

  • ARC = [f(x2)-f(x1)]/ (x2-x1)

<em>In case a)</em>

f(-1)= -5*(-1)-8=5-8= -3          f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

<em>In case b)</em>

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

<em>In case c)</em>

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

3 0
3 years ago
Please help asap 32 pts
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