How many liters of pure acid must be added to 3 liters of 50% acid solution to obtain a 75% acid solution?
1 answer:
If there are 3 liters of 50% acid solution, there must be 1.5 liters of pure acid and 1.5 liters of another liquid.
As it is, 1.5/x = 1/2, where x = total liters of both liquids (here, 3). We use 1.5 because that's how much we have of the other liquid.
If we set 1.5/x = 1/4, x = 6. This is 3 liters more than our original solution, and we only added pure acid.
Our answer is 3 liters of pure acid.
You might be interested in
Answer:
i can see the question in ascending order
No, there are the same y values. View the y value, 1.
Good luck!
Answer:
y=5
Step-by-step explanation:
6-(-3)=9
so...
14-9=5
What? That doesn't make sence! Any way if you mean 1997 to 2014 how many years.
Answer:
11 hours is the most she can afford
Step-by-step explanation:
