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3 years ago

How many liters of pure acid must be added to 3 liters of 50% acid solution to obtain a 75% acid solution?

1 answer:

4 0

If there are 3 liters of 50% acid solution, there must be 1.5 liters of pure acid and 1.5 liters of another liquid.

As it is, 1.5/x = 1/2, where x = total liters of both liquids (here, 3). We use 1.5 because that's how much we have of the other liquid.

If we set 1.5/x = 1/4, x = 6. This is 3 liters more than our original solution, and we only added pure acid.

Our answer is 3 liters of pure acid.

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[ Answer ]

$\boxed{\bold{4au^{2} \ - \ 12u^{2} \ + \ aq \ - \ 3q}}$

[ Explanation ]

Factor: $4u^{2}$ (a - 3) + q(a - 3)

-------------------------------------

Expand $4u^2\left(a-3\right)$ : $4au^2-12u^2$

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Expand

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Answer

$4au^2-12u^2+aq-3q$

$\boxed{\bold{[] \ Eclipsed \ []}}$

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