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2 years ago

How many liters of pure acid must be added to 3 liters of 50% acid solution to obtain a 75% acid solution?

1 answer:

4 0

If there are 3 liters of 50% acid solution, there must be 1.5 liters of pure acid and 1.5 liters of another liquid.

As it is, 1.5/x = 1/2, where x = total liters of both liquids (here, 3). We use 1.5 because that's how much we have of the other liquid.

If we set 1.5/x = 1/4, x = 6. This is 3 liters more than our original solution, and we only added pure acid.

Our answer is 3 liters of pure acid.

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2 years ago

The temperature was -13 F. Write an equivalent statement about the temperature using the absolute value of the number

ch4aika [34]

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3 years ago

Read 2 more answers

A suit originally costing $240 is on sale for 25% off the original price. Sales tax is 7.5%. What is the final cost of the suit?

slava [35]

Answer:

$193.50

Step-by-step explanation:

start by multiplying 240 by .25 (25%) to find out how much is 25% of 240. this equals 60.

then, subtract $60 from $240. equals 180.

next, to add the sales tax, multiply 180 by 0.075 (7.5%) this is $13.50.

lastly, add the tax, which is $13.50, to the suit's sale price, which is $180.

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7 0

2 years ago

lyudmila [28]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Side BC

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

$\therefore \tt \boxed{ \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} = { \bigg(\frac{BC}{EF} \bigg)}^{2} }$

❍ Putting the values, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

$\implies \tt \dfrac{64 \: {cm}^{2} }{12 \: {cm}^{2} } = { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}$

❍ By solving we get,

$\implies \tt \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \sqrt{\dfrac{{(8 \: cm)}^{2} }{ {(11 \: cm)}^{2} }} = \bigg( \dfrac{BC}{15.4 \: cm} \bigg)$

$\implies \tt \dfrac{8 \: cm}{11 \: cm} = \dfrac{BC}{15.4 \: cm}$

$\implies \tt \dfrac{8 \: cm \times 15.4 \: cm}{11 \: cm} = BC$

$\implies \tt \dfrac{123.2 }{11 } cm = BC$

$\implies \tt \purple{ 11.2 \: cm} = BC$

Hence, BC = 11.2 cm.

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

$\rule{280pt}{2pt}$

4 0

2 years ago

Please help me, I need help so bad. make sure to write the full calculation please. If you want bonus points please answer the s

cluponka [151]

Answer:

1. About 9 left. 2. £21 left

Step-by-step explanation:

First, you do 65 ÷ 3 = 21.7 if rounding to the tenths, 21.67 if to the hundredths, and so on. Then you do 21.67 - 12 = 9.67. But since it is cards, I would say about 9 left.

First you add the £20 to the £70 to get £90. then you multiply 7×3 to get £21 spent on books. After that, multiply 12×4 to get £48 spent on games. then do 48 + 21 = 69. 90-69= 21.

Here is the equation....

(70+20)-[(7×3)+(12×4)] = £21

6 0

2 years ago