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3 years ago

3 = q/11 i need it real quick

Mathematics

2 answers:

makkiz [27]3 years ago

7 0

Answer:

$q=33$

Step-by-step explanation:

So we have:

$3=\frac{q}{11}$

Multiply both sides by 11:

$11(3)=(11)\frac{q}{11}$

The right side cancels:

$11(3)=q$

Multiply the left:

$33=q$

Thus, the value of q is 33.

Greeley [361]3 years ago

5 0

Answer:

q = 33

Step-by-step explanation:

3 = q/11 multiply both side by 11

3 * 11 = $\frac{q}{11}$ * 11

33 = q

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Answer:

$\huge\boxed{f(-1) = -7}$

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

$f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3$

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Starting with the first term to the last term:

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WAIT! How is this possible? $-1^4 = -1$ (according to my calculator), and $3 \cdot -1 = -3$ , not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use $-2^2$ as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

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- Exponents

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Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than being "-2 squared" - it's "the negative of of 2 squared."

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Let's move on to our second and third terms.

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Applying the same logic from our first term:

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Combining our terms, we have $3-5-2-3$ .

This comes out to be -7, hence, the value of $f(-1)$ for our function $f(x)=3x^4-5x^2+2x-3$ is -7.

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