All categories

4 years ago

Simplify 8 – 4x – 5 + x. 1 x – 2 2 – 2x 3 – 3x

Mathematics

2 answers:

lara [203]4 years ago

5 0

Simplify the following:

x - 4 x - 5 + 8

Grouping like terms, x - 4 x - 5 + 8 = (8 - 5) + (x - 4 x):

(8 - 5) + (x - 4 x)

x - 4 x = -3 x:

-3 x + (8 - 5)

8 - 5 = 3:

3 - 3 x

Factor 3 out of 3 - 3 x:

Answer: 3 (1 - x) or 3 - 3x

e-lub [12.9K]4 years ago

3 0

8 – 4x – 5 + x

3 - 3x

D. 3 - 3x

You might be interested in

The weight of 3 fruit baskets are shown below. Basket A 12 Kg / Basket B 8 Kg / Basket C 18 kg Which basket is heaviest?

Feliz [49]

I think it is B I hope I am right and helped

5 0

3 years ago

Can somebody help please and thank you :)

Marizza181 [45]

I can help soo first u need to read the question and see what’s its telling u then u got to see what to did like division adding and the other stuff but u are going to divide

4 0

3 years ago

A college has space for 580 studs in the the first class. The college estimates that 65% of the studs who are admitted will accu

Nat2105 [25]

Around 377 students would actually attend (according to the college estimates), off they admit in 580 students. If they want the most students they should admit their maximum.

7 0

4 years ago

Read 2 more answers

Use the Fundamental Theorem of Calculus to find the "area under curve" of

lozanna [386]

Answer:

$\displaystyle A = 300$

General Formulas and Concepts:

Calculus

Integrals

Definite Integrals
Area under the curve
Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 6x + 19

Interval [12, 15]

Step 2: Find Area

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^{15}_{12} {(6x + 19)} \, dx$
[Integral] Rewrite [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{15}_{12} {6x} \, dx + \int\limits^{15}_{12} {19} \, dx$
[Integrals] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 6\int\limits^{15}_{12} {x} \, dx + 19\int\limits^{15}_{12} {} \, dx$
[Integrals] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = 6(\frac{x^2}{2}) \bigg| \limits^{15}_{12} + 19(x) \bigg| \limits^{15}_{12}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle A = 6(\frac{81}{2}) + 19(3)$
Simplify: $\displaystyle A = 300$